这是一个非常简单的问题。
目标:我想用extjs ajax调用更新.json文件。
1)Extjs代码
Ext.Ajax.request({
url : 'hello',
headers: { 'Content-Type': 'application/json' },
jsonData: {
"username" : "admin",
"emailId" : "admin@sivalabs.com"
},
success: function (response) {
//var jsonResp = Ext.util.JSON.decode(response.responseText);
//Ext.Msg.alert("Info","UserName from Server : "+jsonResp.username);
Ext.Msg.alert('success');
},
failure: function (response) {
//var jsonResp = Ext.util.JSON.decode(response.responseText);
//Ext.Msg.alert("Error",jsonResp.error);
Ext.Msg.alert('fail');
}
});
2)控制器类 HelloController.java [路径: src \ com \ tutorialspoint ]
package com.tutorialspoint;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.ui.ModelMap;
@Controller
@RequestMapping("/hello")
public class HelloController{
@RequestMapping(method = RequestMethod.GET)
public String printHello(ModelMap model) {
model.addAttribute("message", "Hello Spring MVC Framework!");
return "hello";
}
}
3)Servlet文件 HelloWeb-servlet.xml [路径: src \ main \ webapp \ WEB-INF ]
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan base-package="com.tutorialspoint" />
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/jsp/" />
<property name="suffix" value=".jsp" />
</bean>
</beans>
4)web.xml [路径: src \ main \ webapp \ WEB-INF ]
<web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
version="3.0">
<display-name>Sample Parent App</display-name>
<servlet>
<servlet-name>ParentServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>ParentServlet</servlet-name>
<url-pattern>*.jsonp</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>HelloWeb</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>HelloWeb</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
<filter>
<filter-name>cross-origin</filter-name>
<filter-class>com.mdstech.controller.SimpleCORSFilter</filter-class>
<init-param>
<param-name>allowedOrigins</param-name>
<param-value>*</param-value>
</init-param>
<init-param>
<param-name>allowedMethods</param-name>
<param-value>GET,POST,OPTIONS,DELETE,PUT,HEAD</param-value>
</init-param>
<init-param>
<param-name>allowedHeaders</param-name>
<param-value>origin, content-type, accept, authorization</param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>cross-origin</filter-name>
<url-pattern>*</url-pattern>
</filter-mapping>
<bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter">
<property name="messageConverters">
<list>
<bean class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter"/>
</list>
</property>
</bean>
</web-app>
当我调用ajax调用时,它会给我一个404错误
无法加载资源:服务器响应状态为404 (未找到)/parent/HelloWeb/hello.jsp
我对extjs很新,所以如果可以,请帮助我。
亲切的问候,