我正在尝试从Android应用程序上传一些文件到我的服务器(通过HTTP POST),我在这里检查了很多问题,但无法让它工作。我希望有人可以帮助我:
我还在URL中包含了一些变量,以验证至少那些变量到达服务器(GET)。
HttpClient httpClient = new DefaultHttpClient();
String url="http://XXXXX.com/files/upload.php?flies=yes&eats=no&friend=yes";
HttpPost httppost = new HttpPost(url);
httppost.addHeader("Content-Type", "multipart/form-data");
String content,response="";
try {
MultipartEntityBuilder builder = MultipartEntityBuilder.create();
builder.setMode(HttpMultipartMode.BROWSER_COMPATIBLE);
builder.addTextBody("randomvar", "42");
//add image file
//String filename="eye.png";
//InputStream is=mContext.getAssets().open(filename);
//builder.addBinaryBody("image", is, ContentType.create("image/png"), filename);
//add text XML file
final File file = new File(mContext.getFilesDir() +"/"+"serverXML.xml");
FileBody fb = new FileBody(file);
builder.addPart("file", fb);
httppost.setEntity(builder.build());
response = EntityUtils.toString(httpClient.execute(httppost).getEntity(), "UTF-8");
Log.i(TAG, "RESPONSE FROM SERVER: "+response);
} catch (IOException e) {
Log.i(TAG, "Exception: "+response);
e.printStackTrace();
}
这会运行并从服务器获得响应。以下是$ _GET,$ _POST,$ _FILES:
的vardump
我希望POST拥有文件和变量
在我的Eclipse Logcat中,我在使用MultiPartEntityBuilder后看到以下内容:
10-06 02:36:57.231: D/dalvikvm(15888): DexOpt: couldn't find static field Lorg/apache/http/message/BasicHeaderValueParser;.INSTANCE
10-06 02:36:57.241: W/dalvikvm(15888): VFY: unable to resolve static field 5966 (INSTANCE) in Lorg/apache/http/message/BasicHeaderValueParser;
10-06 02:36:57.241: D/dalvikvm(15888): VFY: replacing opcode 0x62 at 0x001b
10-06 02:36:57.241: D/dalvikvm(15888): DexOpt: couldn't find static field Lorg/apache/http/message/BasicHeaderValueFormatter;.INSTANCE
10-06 02:36:57.241: W/dalvikvm(15888): VFY: unable to resolve static field 5960 (INSTANCE) in Lorg/apache/http/message/BasicHeaderValueFormatter;
我想我已经正确地包含了所有必需的库:
修改
我能够解决这个问题,我的解决方案在下面的答案中描述
答案 0 :(得分:5)
我很幸运能在Stackoverflow中找到一个Answer by Krystian来解决我的问题。
添加边界后,它开始工作。我不得不将它添加到HTTP Post
String boundary = "-------------" + System.currentTimeMillis();
httppost.setHeader("Content-type", "multipart/form-data; boundary="+boundary);
和实体
MultipartEntityBuilder builder = MultipartEntityBuilder.create();
builder.setMode(HttpMultipartMode.BROWSER_COMPATIBLE);
builder.setBoundary(boundary);
现在我收到了服务器中的所有内容:
10-06 13:16:06.977: I/UploadFileAsync(31506): RESPONSE FROM SERVER: Array
10-06 13:16:06.977: I/UploadFileAsync(31506): (
10-06 13:16:06.977: I/UploadFileAsync(31506): [flies] => yes
10-06 13:16:06.977: I/UploadFileAsync(31506): [eats] => no
10-06 13:16:06.977: I/UploadFileAsync(31506): [friend] => yes
10-06 13:16:06.977: I/UploadFileAsync(31506): )
10-06 13:16:06.977: I/UploadFileAsync(31506): Array
10-06 13:16:06.977: I/UploadFileAsync(31506): (
10-06 13:16:06.977: I/UploadFileAsync(31506): [randomvar] => 42
10-06 13:16:06.977: I/UploadFileAsync(31506): [mystr] => blaka
10-06 13:16:06.977: I/UploadFileAsync(31506): )
10-06 13:16:06.977: I/UploadFileAsync(31506): Array
10-06 13:16:06.977: I/UploadFileAsync(31506): (
10-06 13:16:06.977: I/UploadFileAsync(31506): [file] => Array
10-06 13:16:06.977: I/UploadFileAsync(31506): (
10-06 13:16:06.977: I/UploadFileAsync(31506): [name] => serverXML.xml
10-06 13:16:06.977: I/UploadFileAsync(31506): [type] => application/octet-stream
10-06 13:16:06.977: I/UploadFileAsync(31506): [tmp_name] => /tmp/phpdmEsn2
10-06 13:16:06.977: I/UploadFileAsync(31506): [error] => 0
10-06 13:16:06.977: I/UploadFileAsync(31506): [size] => 3548
10-06 13:16:06.977: I/UploadFileAsync(31506): )
10-06 13:16:06.977: I/UploadFileAsync(31506): )
答案 1 :(得分:1)
你必须像这样工作
public void connectForMultipart() throws Exception {
con = (HttpURLConnection) ( new URL(url)).openConnection();
con.setRequestMethod("POST");
con.setDoInput(true);
con.setDoOutput(true);
con.setRequestProperty("Connection", "Keep-Alive");
con.setRequestProperty("Content-Type", "multipart/form-data; boundary=" + boundary);
con.connect();
os = con.getOutputStream();
}
public void addFormPart(String paramName, String value) throws Exception {
writeParamData(paramName, value);
}
public void addFilePart(String paramName, String fileName, byte[] data) throws Exception {
os.write( (delimiter + boundary + "\r\n").getBytes());
os.write( ("Content-Disposition: form-data; name=\"" + paramName + "\"; filename=\"" + fileName + "\"\r\n" ).getBytes());
os.write( ("Content-Type: application/octet-stream\r\n" ).getBytes());
os.write( ("Content-Transfer-Encoding: binary\r\n" ).getBytes());
os.write("\r\n".getBytes());
os.write(data);
os.write("\r\n".getBytes());
}
public void finishMultipart() throws Exception {
os.write( (delimiter + boundary + delimiter + "\r\n").getBytes());
}
httpPost.setEntity(entity);
HttpResponse response = httpClient.execute(httpPost);
BufferedReader reader = new BufferedReader(new InputStreamReader(response.getEntity().getContent(), "UTF-8"));
String sResponse;
while ((sResponse = reader.readLine()) != null)
{
s = s.append(sResponse);
}
if(response.getStatusLine().getStatusCode() == HttpStatus.SC_OK)
{
return s.toString();
}else
{
return "{\"status\":\"false\",\"message\":\"Some error occurred\"}";
}
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
代替图像,您可以发送任何内容(在您的情况下为xml
文件),您希望...如果它创建了一些heck然后
你应该将大文件分成小部分,然后尝试发送。并在服务器上加入这个小部分。
在我的情况下httpmime-4.2.1-1.jar
仅在此代码中需要