Question

我开始使用Spring框架，并且我试图围绕bean概念。我有一个xml文件：

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd">

  <bean id= "currentDateService" class ="xx.CurrentDateSerivceimpl" />
</beans>

获得当前日期的课程：

public class CurrentDateServiceImpl implements CurrentDateService {
    public LocalDate getCurrentDate() {
        return LocalDate.now() ;

    }

我想要完成的是一个简单的@test断言，如果bean值与我提供的当前日期相同。

我所坚持的是：

@Test
public void test() {
    ApplicationContext context = new ClassPathXmlApplicationContext("application-context.xml");
    CurrentDateServiceImpl currentDateServiceObj = (CurrentDateServiceImpl) context.getBean("currentDateService");
    LocalDate date = LocalDate.now();
    LocalDate date2 = "the value of the bean";
    assertEquals(date, date2);
}

我不知道如何在测试中提供bean的价值，我想知道如何完成它以及是否有任何好的教程/文档除了弹簧文档本身

编辑：

package lt.insoft.app.bl.service.impl;

import static org.junit.Assert.assertEquals;

import java.time.LocalDate;

import lt.insoft.app.bl.service.CurrentDateService;
import lt.insoft.app.bl.service.CurrentDateServiceFormat;

import org.junit.Test;
import org.junit.runner.RunWith;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;
import org.springframework.test.context.ContextConfiguration;
import org.springframework.test.context.junit4.SpringJUnit4ClassRunner;

@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(locations = { "file:src/main/resources/META-INF/application-context.xml" })
public class CurrentDateServiceImplTest {

@Autowired
CurrentDateService service; 
CurrentDateServiceFormat service2;


    @Test
    public void test() {

        LocalDate date = LocalDate.now();
        LocalDate date2 = service.getCurrentDate();     
        String date3 = service2.formatCurrentDate();
        System.out.println(date3);
        assertEquals(date, date2);
    }

}

为什么不打印格式化日期？

Answer 1

使用弹簧支架进行测试。代码将更清晰，更容易理解。

@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(locations = {"application-context.xml"})
public class TestClass{

@Autowired
CurrentDateService service;

@Test
public void test() {

    LocalDate date = LocalDate.now();
    LocalDate date2 = service.getCurrentDate();
    assertEquals(date, date2);
}
}

我想你想做这样的事情：

public class CurrentDateServiceImpl implements CurrentDateService {
    public LocalDate getCurrentDate() {
        return LocalDate.now() ;

    }
}

public class CurrentDateServiceFormatImpl implements CurrentDateServiceFormat{
    private static final DateTimeFormatter FORMATTER = DateTimeFormatter.ofPattern("dd-MM-yyyy");

    CurrentDateService service;

    public void myMethod(){
       return service.getCurrentDate().format(FORMATTER); 
    }

    public void setService(CurrentDateService service){
       this.service = service;
    }
}

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd">

  <bean id= "currentDateService" class ="xx.CurrentDateSerivceimpl" />
  <bean id= "CurrentDateServiceFormat" class ="xx.CurrentDateServiceFormatImpl">
     <property name="service" id-ref="currentDateService"/>
  </bean>
</beans>

春豆价值注入

1 个答案: