Question

有没有办法从变量中将数据插入表中？可变内容示例：

123;1;500;some text here;
145;0;250;and some more text;
146;1;0;;
146;0;3;this field in previous line is empty;

列分隔符：;
行分隔符：\r\n

Answer 1

如果; - 已分隔内容位于文件中，则可以使用BULK INSERT。有关此问题的StackOverflow问题，您可以找到here。因此，将变量的内容转储到文件中并使用BULK INSERT将是一种方法。

Answer 2

解决方案就像......

declare @var varchar(100)

set @var= '123;1;500;some text here;'


select @var as variable,CHARINDEX(';',@var) as col1
,CHARINDEX(';',@var,CHARINDEX(';',@var)+1) as col2 
,CHARINDEX(';',@var,CHARINDEX(';',@var,CHARINDEX(';',@var)+1)+1) as col3
,CHARINDEX(';',@var,CHARINDEX(';',@var,CHARINDEX(';',@var,CHARINDEX(';',@var)+1)+1)+1) as col4
into #temp

select * from #temp 

select SUBSTRING(variable,0,col1) as Col1Text 
,replace(SUBSTRING(variable,col1,col2-col1),';','') as Col2Text
,replace(SUBSTRING(variable,col2,col3-col2),';','') as Col2Text
,replace(SUBSTRING(variable,col3,col4-col3),';','') as Col2Text 
from #temp 



drop table #temp

Answer 3

DECLARE @table_var TABLE(
col_list VARCHAR(50)
 )

INSERT INTO @table_var VALUES ('123;1;500;some text here');
INSERT INTO @table_var VALUES ('145;0;250;and some more text;');
INSERT INTO @table_var VALUES ('146;1;0;;');
INSERT INTO @table_var VALUES ('146;0;3;this field');

SOL 1 :
SELECT DISTINCT S.a.value('(/H/r)[1]', 'VARCHAR(25)') AS col1
, S.a.value('(/H/r)[2]', 'VARCHAR(25)') AS col2
, S.a.value('(/H/r)[3]', 'VARCHAR(25)') AS col3
, S.a.value('(/H/r)[4]', 'VARCHAR(25)') AS col4
FROM
(
SELECT *,CAST (N'<H><r>' + REPLACE(col_list, ';', '</r><r>')  + '</r></H>' AS XML) AS [vals]
FROM @table_var) d 
CROSS APPLY d.[vals].nodes('/H/r') S(a)

Sol 2:
SELECT  col_list,
   NewXML.value('/col_list[1]/Attribute[1]', 'varchar(25)') AS [col1],
   NewXML.value('/col_list[1]/Attribute[2]', 'varchar(25)') AS [col2],
   NewXML.value('/col_list[1]/Attribute[3]', 'varchar(25)') AS [col3],
   NewXML.value('/col_list[1]/Attribute[4]', 'varchar(25)') AS [col4]
FROM   @table_var t1
   CROSS APPLY (SELECT XMLEncoded=(SELECT col_list AS [*]
                                   FROM   @table_var t2
                                   WHERE  t1.col_list = t2.[col_list]
                                   FOR XML PATH(''))) EncodeXML
   CROSS APPLY (SELECT NewXML=Cast('<col_list><Attribute>'
                                   + Replace(XMLEncoded, ';', '</Attribute><Attribute>')
                                   + '</Attribute></col_list>' AS XML)) CastXML

使用T-SQL从CSV格式的文本变量中将数据插入表中

3 个答案: