Question

 array (size=3)
 0 => 
  object(stdClass)[20]
    public 'id' => string '12' (length=2)
    public 'cities' => string 'narayangarh' (length=11)
    public 'c_id' => string '24' (length=2)
    public 'places' => string 'pulchowk' (length=8)
 1 => 
  object(stdClass)[21]
    public 'id' => string '13' (length=2)
    public 'cities' => string 'narayangarh' (length=11)
    public 'c_id' => string '24' (length=2)
    public 'places' => string 'sahidchowk' (length=10)
 2 => 
  object(stdClass)[22]
    public 'id' => string '14' (length=2)
    public 'cities' => string 'narayangarh' (length=11)
    public 'c_id' => string '24' (length=2)
    public 'places' => string ' lionschowk' (length=11)

在这个数组中，有一个常见的cities＆＃39; narayangarh＆＃39;共同的'c_id'重复三次，并且'places'与'id'不同array_unique()。我怎样才能获得如下输出：

纳拉英格阿尔
- pulchowk
- sahidchowk
- lionschowk

所以那个'narayangarh＆＃39;是父母和＆＃39; pulchowk＆＃39; sahidchowk＆＃39;和＆＃39; lionschowk＆＃39;是孩子。我无法通过正常的foreach循环实现。是否可以通过{{1}}。

Answer 1

让我们假装你的城市目前存储在名为$ a的数组中。

创建其他数组或映射$ b
循环浏览$ a
将a-＆gt;地点附加到b [c_id] - ＆gt;地点
您的城市现在处于缩写形式的变量$ b

例如

$b = array();
foreach ($a as $city) {
  // If city already is in "$b"
  if ( array_key_exists($city->c_id, $b) ) {
    array_push($b[$city->c_id]->places, $city->places);
  } else {
    $b[$city->c_id] = $city;
    $b[$city->c_id]->places = array($city->places);
  }
}
var_dump($b);

array (size=1)
 0 => 
  object(stdClass)[20]
    public 'id' => string '12' (length=2)
    public 'cities' => string 'narayangarh' (length=11)
    public 'c_id' => string '24' (length=2)
    public 'places' => array (size=3) 
                0=> string 'pulchowk' (length=8)                 
                1=> string 'sahidchowk' (length=10)
                2=> string 'lionschowk' (length=11)

编辑：$ b [$ city]更改为$ b [$ city-＆gt; c_id] swapped array_key_exists代码块与else代码块

使数组唯一并显示其重复的子项

1 个答案: