Question

请帮助out.ym使用php excel与laravel但是每当我尝试将excel文件导入数据库时我都会收到错误＆＃34;加载文件时出错＆＃34; update.xlsx＆＃34;：无法打开localhost： 9090 / xls / update.xlsx供阅读！文件不存在。＆＃34;。

我的xls文件夹放在我的公共目录中，并且正在使用composer加载phpexcel.Kindly帮助我知道出错了什么。谢谢提前

这是我的代码：

<?php
/************************ YOUR DATABASE CONNECTION START HERE   ****************************/

define ("DB_HOST", "lhost"); // set database host
define ("DB_USER", "root"); // set database user
define ("DB_PASS",""); // set database password
define ("DB_NAME","name"); // set database name

// $link = mysql_connect(DB_HOST, DB_USER, DB_PASS) or die("Couldn't make connection.");
// $db = mysql_select_db(DB_NAME, $link) or die("Couldn't select database");

$databasetable = "applicant";

$con = new mysqli(DB_HOST, DB_USER,DB_PASS,DB_NAME);
/************************ YOUR DATABASE CONNECTION END HERE  ****************************/


set_include_path(get_include_path() . PATH_SEPARATOR . 'Classes/');


// This is the file path to be uploaded.
 $inputFileName = asset("xls/".$filename);; 

try {
    $objPHPExcel = PHPExcel_IOFactory::load($inputFileName);
} catch(Exception $e) {
    die('Error loading file "'.pathinfo($inputFileName,PATHINFO_BASENAME).'": '.$e->getMessage());
}


$allDataInSheet = $objPHPExcel->getActiveSheet()->toArray(null,true,true,true);
$arrayCount = count($allDataInSheet);  // Here get total count of row in that Excel sheet


for($i=2;$i<=$arrayCount;$i++)
{
$surname    = trim(strtoupper($allDataInSheet[$i]["A"]));
$othernames = trim(strtoupper($allDataInSheet[$i]["B"]));
$address    = strtoupper($allDataInSheet[$i]["C"]);
$lga        = trim(strtoupper($allDataInSheet[$i]["D"]));
$sex        = trim(strtoupper($allDataInSheet[$i]["E"]));
$dob        = trim(strtoupper($allDataInSheet[$i]["F"]));
$genotype   = trim(strtoupper($allDataInSheet[$i]["G"]));
$blood_grp  = trim(strtoupper($allDataInSheet[$i]["H"]));
$phone      = trim(strtoupper($allDataInSheet[$i]["I"]));
$email      = trim(strtoupper($allDataInSheet[$i]["J"]));
$occupation = trim(strtoupper($allDataInSheet[$i]["K"]));
$place_emp  = trim(strtoupper($allDataInSheet[$i]["L"]));
$facility   = trim(strtoupper($allDataInSheet[$i]["M"]));
$medical_his = trim(strtoupper($allDataInSheet[$i]["N"]));
$allergy    = trim(strtoupper($allDataInSheet[$i]["O"]));
$reg_frm    = trim(strtoupper($allDataInSheet[$i]["P"]));
$reg_to     = trim(strtoupper($allDataInSheet[$i]["Q"]));
$collector  = trim(strtoupper($allDataInSheet[$i]["R"]));
$form_no    = trim(strtoupper($allDataInSheet[$i]["S"]));
$tell_no    = trim(strtoupper($allDataInSheet[$i]["T"]));
$amt_paid   = trim(strtoupper($allDataInSheet[$i]["U"]));

$query = "SELECT surname FROM `applicant` WHERE `surname` = '$surname' and `othernames` = '$othernames'";
$sql = $con->query($query);
$recResult = mysqli_fetch_array($sql);
$existName = $recResult["surname"];
if($existName=="") {
$insertTable= $con->query("insert into `applicant` (surname, othernames,address,lga,sex,dob,genotype,blood_grp,phone,email,occupation,place_emp,facility,medical_his,allergy,reg_frm,reg_to,collector,form_no,tell_no,amt_paid) 
    values('".$surname."', '".$othernames."','".$address."','".$lga."','".$sex."','".$dob."',
        '".$genotype."','".$blood_grp."','".$phone."','".$email."','".$occupation."',
        '".$place_emp."','".$facility."','".$medical_his."','".$allergy."','".$reg_frm."',
        '".$reg_to."','".$collector."','".$form_no."','".$tell_no."','".$amt_paid."');");


$msg = 'Record has been added';
} 
else 
{
$msg = 'Record already exist';
}
}
echo "<div class='alert alert-info'>".$msg."</div>";


?>

Answer 1

我不确定什么是“composer”以及asset()函数应该做什么，但通常对于PHP脚本的文件上传，你使用“mime / multipart”web表单一个文件输入，然后PHP运行时将使用该文件并使其在$_FILES数组中可用。有关详细信息，请阅读PHP manual on handling file uploads。

Answer 2

PHPExcel无法仅通过本地文件系统从URL打开文件。由于您正在使用的网址（localhost）表明该文件位于服务器的文件系统上，因此我们建议使用完整的文件系统路径

PHPExcel文件不存在

2 个答案: