Question

我想从数据库中获取记录并将其显示在数据表中，但是当我在浏览器中运行此PHP代码时，它只在简单的表中显示记录。我希望这个结果在jquery数据表中进行搜索和排序。

数据表的javascript函数（使用jquery.dataTables.js）

    <script type="text/javascript" language="javascript">
        $(document).ready(function() {
        ('#datatable').DataTable();
        })
    </script>

用于获取记录的mysql函数

    <?php 
        $con=mysql_connect("localhost","root","");
        mysql_select_db("runindia",$con);
        $query="select *from admin_login";
        $rs=mysql_query($query,$con);
   ?>
<div class="container">
   <table class="table table-bordered table-responsive table-hover display" id="datatable">
         <thead>
             <th> Admin ID</th>
             <th> User Name</th>
             <th> First Name</th>
             <th> Last Name</th>
             <th> Email</th>
        </thead>
       <?php 
            while($r=mysql_fetch_array($rs))
       { ?>

       <tbody>
           <tr>
                <td><?php echo $r['admin_id'];?></td>
                <td><?php echo $r['username'];?></td>
                <td><?php echo $r['first_name'];?></td>
                <td><?php echo $r['last_name'];?></td>
                <td><?php echo $r['email'];?></td>
           </tr>
      </tbody>
   <?php  
   } //closing while
   mysql_close($con);//mysql connection close
   ?>
 </table>

Answer 1

尝试保持＆＃39; tbody＆＃39;走出循环：

<table class="table table-bordered table-responsive table-hover display" id="datatable">
         <thead>
             <th> Admin ID</th>
             <th> User Name</th>
             <th> First Name</th>
             <th> Last Name</th>
             <th> Email</th>
        </thead>
<tbody>
       <?php 
            while($r=mysql_fetch_array($rs))
       { ?>


           <tr>
                <td><?php echo $r['admin_id'];?></td>
                <td><?php echo $r['username'];?></td>
                <td><?php echo $r['first_name'];?></td>
                <td><?php echo $r['last_name'];?></td>
                <td><?php echo $r['email'];?></td>
           </tr>

   <?php  
   } //closing while
   mysql_close($con);//mysql connection close
   ?>
</tbody>
 </table>

或尝试更好的方法，例如通过JSON格式的AJAX调用获取数据

Answer 2

<?php 
        $con=mysqli_connect("localhost","root","", "runindia");
        $query="select * from admin_login";
        $rs=mysqli_query($con, $query);
   ?>
<div class="container">
   <table class="table table-bordered table-responsive table-hover display" id="datatable">
         <thead>
             <th> Admin ID</th>
             <th> User Name</th>
             <th> First Name</th>
             <th> Last Name</th>
             <th> Email</th>
        </thead>
       <?php 
            while($r = mysqli_fetch_array($rs, MYSQLI_ASSOC))
       { ?>

       <tbody>
           <tr>
                <td><?php echo $r['admin_id'];?></td>
                <td><?php echo $r['username'];?></td>
                <td><?php echo $r['first_name'];?></td>
                <td><?php echo $r['last_name'];?></td>
                <td><?php echo $r['email'];?></td>
           </tr>
      </tbody>
   <?php  
   } //closing while
   mysqli_close($con);//mysqli connection close
   ?>
 </table>

在jQuery数据表中显示数据库记录

2 个答案: