Question

我有一些设备管理员权限应用程序与一些广播公司（我正在注册和在正确的时间注册！），问题是我的应用程序启动设备启动，我没有任何过滤意图这个意图，让我的应用程序开始！，请参阅AndroidManifest.xml，如下所示：

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.winacro.xyz"
android:versionCode="1"
android:versionName="1.0" >

<!--uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED" /-->
<uses-sdk
    android:minSdkVersion="16"
    android:targetSdkVersion="19" />

<application
    android:allowBackup="true"
    android:icon="@drawable/ic_launcher"
    android:label="@string/app_name"
    android:theme="@style/Fullscreen" >

    <activity
        android:name="com.winacro.xyz.SplashScreen"
        android:label="@string/app_name"
        android:screenOrientation="portrait"
        android:theme="@style/Fullscreen" >

    </activity>

    <activity
        android:name="com.winacro.xyz.Boot"
        android:label="@string/app_name"
        android:screenOrientation="portrait"
        android:theme="@style/Fullscreen" >
        <intent-filter>
            <action android:name="android.intent.action.MAIN" />
            <category android:name="android.intent.category.LAUNCHER" />
        </intent-filter>

    </activity>

    <activity
        android:name="com.winacro.xyz.Xyz"
        android:screenOrientation="portrait"
        android:theme="@style/Fullscreen"
        android:label="@string/app_name" />

    <activity
        android:name="com.winacro.xyz.Locked"
        android:screenOrientation="portrait"
        android:theme="@style/Fullscreen"
        android:label="@string/app_name" />


    <service
        android:name="com.winacro.xyz.xyzService"
        android:enabled="true" > 

    </service>

    <receiver android:name="com.winacro.xyz.MyBroadcastReceiver" >
        <intent-filter>
            <action android:name="android.hardware.usb.action.USB_DEVICE_DETACHED" />
        </intent-filter>

        <meta-data
            android:name="android.hardware.usb.action.USB_DEVICE_DETACHED"
            android:resource="@xml/device_filter" />
    </receiver>

     <receiver android:name="com.winacro.xyz.activateSERVICE" >
        <intent-filter>
            <action android:name="android.hardware.usb.action.USB_DEVICE_ATTACHED" />
        </intent-filter>

        <meta-data
            android:name="android.hardware.usb.action.USB_DEVICE_ATTACHED"
            android:resource="@xml/device_filter" />
    </receiver>

    <!-- Device Admin Receiver -->
    <receiver
        android:name="com.winacro.xyz.DeviceAdminR"
        android:permission="android.permission.BIND_DEVICE_ADMIN" >
        <intent-filter>

            <!-- This action is required -->
            <action android:name="android.app.action.DEVICE_ADMIN_ENABLED" />
        </intent-filter>

        <!-- This is required this receiver to become device admin component. -->
        <meta-data
            android:name="android.app.device_admin"
            android:resource="@xml/policies" />
    </receiver>

</application>

正如您所看到的，我在清单中注释了RECEIVE_BOOT_COMPLETED，它应该将Boot事件路由到我的但仍然是我的应用程序从activateSERVICE.java开始，如下所示：

public class activateSERVICE extends BroadcastReceiver {

@Override
public void onReceive(Context context, Intent intent) {
    Toast.makeText(context, "Boolean Set True", Toast.LENGTH_SHORT).show();
    //Intent startActSerIntent = new Intent(context, Boot.class);
    Intent i = new Intent();
    i.setClassName("com.winacro.xyz", "com.winacro.xyz.Boot");
    i.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
    Intent startService = new Intent(context, xyzService.class);
    context.startService(startService);
    context.startActivity(i);
    //context.startActivity(startActSerIntent);
    xyzService.USBpluggedIn = true;
}

}

请告诉我为什么我的应用程序启动？（我确认我的应用程序从activateSERVICE启动是因为只有这个代码设置变量USBpluggedIn = true;并且只有在设置我的应用程序启动xyzService时才会这样做。正在开始的课程。）

Answer 1

您正在接收android.hardware.usb.action.USB_DEVICE_ATTACHED广播，因为某些USB设备在启动时连接到设备。

应用程序不应该在Boot Up BUT启动时启动

1 个答案: