Question

我有一个文件bundle.crd。 itens就像这样

col1 val1 val2 val3 val4 
col2 val1 val2 val3 val4 
col4 val1 val2 val3 val4 
col5 val1 val2 val3 val4 
col6 val1 val2 val3 val4 
col7 val1 val2 val3 val4

我需要以下列格式将其导入excel文件。

col1  col2  col3  col4  col5  col6 col7
-------------------------------------------
val1  val1  val1  val1  val1  val1  val1 
val2  val2  val2  val2  val2  val2  val2 
val3  val3  val3  val3  val3  val3  val3
val4  val4  val4  val4  val4  val4  val4

我尝试了这段代码，但它无效


    lines = (line for line in stripped if line)
        grouped = itertools.izip(*[lines] * 3)
        with open('extracted.csv', 'w') as out_file:
            writer = csv.writer(out_file)
            #writer = csv.writer(out_file, dialect=csv.excel)
            writer.writerow(('title', 'intro', 'tagline'))
            writer.writerows(grouped)

请帮助

Answer 1

您是否将线条拆分为单元格？

以下是一个示例，如何转置列表列表：

>>> values
[['col1', 'val1', 'val2', 'val3', 'val4'], ['col2', 'val1', 'val2', 'val3', 'val4'], ['col4', 'val1', 'val2', 'val3', 'val4'], ['col5', 'val1', 'val2', 'val3', 'val4'], ['col6', 'val1', 'val2', 'val3', 'val4'], ['col7', 'val1', 'val2', 'val3', 'val4']]
>>> zip(*values)
[('col1', 'col2', 'col4', 'col5', 'col6', 'col7'), ('val1', 'val1', 'val1', 'val1', 'val1', 'val1'), ('val2', 'val2', 'val2', 'val2', 'val2', 'val2'), ('val3', 'val3', 'val3', 'val3', 'val3', 'val3'), ('val4', 'val4', 'val4', 'val4', 'val4', 'val4')]

原始数据优秀

1 个答案: