cout不打印函数的返回值？

Question

我正在做一个问题，我必须通过一个函数传递一个数组，并返回用户输入的索引范围内的最小整数。问题是cout没有显示被调用函数的返回值：

有人能告诉我什么是错的吗？

#include <iostream>;
#include <array>;
using namespace std;

int minInARange (int array[], int lowIndex, int highIndex);

int main()
{
    int myArray[15];

    for (int i = 0; i <15; i++)
    {
        myArray[i] = 15 + rand() % (55 - 15 + 1);
    }

    for (int i = 0; i < 15; i++)
    {
        cout << myArray[i] << " ";
    }
    cout << endl;

    int lowIndex = 0;
    int highIndex = 0;

    cout << "Enter in a low index of the array (0-14): " << endl;
    cin >> lowIndex;
    cout << "Enter in a higher index of the array (0-14): " << endl;
    cin >> highIndex;

    cout << "The lowest number in the range of array indices is: ";
    cout << minInARange(myArray, lowIndex, highIndex) << endl;

    return 0;
}

int minInARange (int array[], int lowIndex, int highIndex)
{
    int lowestNum = array[lowIndex];
    for (int i = 0; i < highIndex - lowIndex; i++)
    {
        if (array[i] < lowestNum)
        {
            lowestNum = array[i];
        }
    }
    return lowestNum;
}

Answer 1

int minInARange (int array[], int lowIndex, int highIndex) {
   cout << "lo:" << lowIndex << " hi:" << highIndex << endl;
   for (int i=lowIndex; i<highIndex; i++) //maybe <=, depends what you want
     cout << "Tock:" << i << endl;
     ....
}