slice_mut for＆amp; mut [T]

Question

为什么{amp; mut [T]没有实现MutableSlice::slice_mut？

每晚0.12.0测试rustc（b2d4eb186 2014-10-02 15:57:19 +0000）：

fn sort<T>(v: &mut [T]){
    let (l, r) = v.split_at_mut(2); // Ok
    let len = v.slice_mut(1u, 3u).len(); // error: type `&mut [T]` does not implement any method in scope named `slice_mut`
}

#[test]
fn it_works() {
    let mut v = [1i, 2, 3, 4, 5, 6];
    sort(v);
}

Answer 1

该方法had been removed，但the change has since been rolled back。 sort函数compiles right now的第二行。