我有一个问题或解释要问你......
我正在开发zf2应用程序并且我试图制作前/后端结构,所以我再添加一个名为Admin的模块,现在我想制作路径结构,如www.domain.com / [/:controller [/:action] [ /:id]]] frontend和www.domain.com/admin [/:controller [/:action] [/:id]]];
所以对于前端没有任何问题,并且每件事情都很好但是在后端结构中我总是得到"请求的URL无法通过路由匹配。"错误。
我当前的module.config.php文件是这样的:
<?php
return array(
'router' => array(
'routes' => array(
'admin' => array(
'type' => 'Zend\Mvc\Router\Http\Literal',
'options' => array(
'route' => '/admin/',
'defaults' => array(
'controller' => 'Admin\Controller\Index',
'action' => 'index',
),
),
),
// The following is a route to simplify getting started creating
// new controllers and actions without needing to create a new
// module. Simply drop new controllers in, and you can access them
// using the path /application/:controller/:action
'default' => array(
'type' => 'Literal',
'options' => array(
'route' => '/admin',
'defaults' => array(
'__NAMESPACE__' => 'Admin\Controller',
'controller' => 'Index',
'action' => 'index',
),
),
'may_terminate' => true,
'child_routes' => array(
'default' => array(
'type' => 'Segment',
'options' => array(
'route' => '/admin[/:controller[/:action]]',
'constraints' => array(
'controller' => '[a-zA-Z][a-zA-Z0-9_-]*',
'action' => '[a-zA-Z][a-zA-Z0-9_-]*',
),
'defaults' => array(
'action' => 'index'
),
),
),
),
),
),
),
'service_manager' => array(
'abstract_factories' => array(
'Zend\Cache\Service\StorageCacheAbstractServiceFactory',
'Zend\Log\LoggerAbstractServiceFactory',
),
'aliases' => array(
'translator' => 'MvcTranslator',
),
),
'translator' => array(
'locale' => 'en_US',
'translation_file_patterns' => array(
array(
'type' => 'gettext',
'base_dir' => __DIR__ . '/../language',
'pattern' => '%s.mo',
),
),
),
'controllers' => array(
'invokables' => array(
'Admin\Controller\Index' => 'Admin\Controller\IndexController',
'Admin\Controller\Login' => 'Admin\Controller\LoginController'
),
),
'view_manager' => array(
'display_not_found_reason' => true,
'display_exceptions' => true,
'doctype' => 'HTML5',
'not_found_template' => 'error/404',
'exception_template' => 'error/index',
'template_map' => array(
// 'layout/layout' => __DIR__ . '/../view/layout/layout.phtml',
'layout/admin' => __DIR__ . '/../view/layout/admin.phtml',
'layout/login' => __DIR__ . '/../view/layout/login.phtml',
'admin/index/index' => __DIR__ . '/../view/admin/index/index.phtml',
'error/404' => __DIR__ . '/../view/error/404.phtml',
'error/index' => __DIR__ . '/../view/error/index.phtml',
),
'template_path_stack' => array(
__DIR__ . '/../view',
),
),
// Placeholder for console routes
'console' => array(
'router' => array(
'routes' => array(
),
),
),
);
答案 0 :(得分:1)
好的,我自己弄清楚了;
我不了解路线;
所以在admin / module.config.php中 我试图设置路由到/ admin / controller / action我最终做的是/ admin / admin / controller / action
新配置:
'admin' => array(
'type' => 'Segment',
'options' => array(
'route' => '/admin',
'defaults' => array(
'__NAMESPACE__' => 'Admin\Controller',
'module' => 'admin',
'controller' => 'Index',
'action' => 'index',
),
),
'may_terminate' => true,
'child_routes' => array(
'default' => array(
'type' => 'Segment',
'options' => array(
'route' => '[/:controller[/:action]]',
'constraints' => array(
'module' => '[a-zA-Z][a-zA-Z0-9_-]*',
'controller' => '[a-zA-Z][a-zA-Z0-9_-]*',
'action' => '[a-zA-Z][a-zA-Z0-9_-]*'
),
'defaults' => array(
'module' => 'admin'
),
),
),
),
),