Question

我一直在家里使用Python制作基于文本的游戏，并且在玩家和敌人之间创建一小部分战斗时遇到了麻烦。战斗应该包括两个随机卷;一个为玩家，另一个为外星人。如果外星人高于玩家，那么+1应该被添加到alien_wins计数器，如果玩家获胜+1，则应该添加到player_wins计数器。

我想要发生的是当player_wins计数器达到3时，循环将停止并产生一条消息，当alien_ wins达到3时也应该发生同样的情况，但是我无法完成这项工作。任何帮助将不胜感激，谢谢！

import random
from Tkinter import *

def Fight():

    player_wins = 0
    alien_wins = 0

    while player_wins <= 3:

        player_roll = random.randint(0, 10)
        alien_roll = random.randint(0, 7)

        if player_roll > alien_roll:
            contents.set("You manage to fire a shot of your laser pistol and the alien backs off.")
            player_wins += 1
            return

        elif alien_roll > player_roll:
            contents.set("The alien reaches out and strikes you with its claws.")
            alien_wins += 1
            return

        elif alien_roll == player_roll:
            contents.set("You both grapple eachother and eventually back off.")        
            return

            if player_wins == 3:
                contents.set("You manage to overcome the alien. It leaps from wall to wall and crawls into the vents.")
                win = True
                break
            elif alien_wins == 3:
                contents.set("You lose the fight to the alien. Game Over!")
                break

base = Tk()

contents = StringVar()
display = Message(base, textvariable = contents, relief=RAISED)
display.pack()

enterbutton = Button(base, text = 'Try Again', command = Fight).pack()

base.mainloop()

Answer 1

当任一条件（点数＆lt; = 3）为True时，您希望继续战斗（循环）。您需要在while循环中添加另一个条件。

你只想在战斗结束后从该功能返回，所以删除所有这些返回并在战斗结束后添加一个在循环之外。此外，您只想在战斗结束后创建消息。

def Fight():

    player_wins = 0
    alien_wins = 0

    while player_wins <= 3 and alien_wins <= 3:

        player_roll = random.randint(0, 10)
        alien_roll = random.randint(0, 7)

        if player_roll > alien_roll:
            contents.set("You manage to fire a shot of your laser pistol and the alien backs off.")
            player_wins += 1

        elif alien_roll > player_roll:
            contents.set("The alien reaches out and strikes you with its claws.")
            alien_wins += 1

        elif alien_roll == player_roll:
            contents.set("You both grapple eachother and eventually back off.")        

    if player_wins == 3:
        contents.set("You manage to overcome the alien. It leaps from wall to wall and crawls into the vents.")
        win = True
    elif alien_wins == 3:
        contents.set("You lose the fight to the alien. Game Over!")
    return

Answer 2

我清理了一些东西。循环的主要问题是通过使循环依赖于player_wins和alien_wins <= 3来解决的。这样，只要其中一个命中3，循环就会终止，然后控制转到下面的if/else语句，然后设置获胜者。

def Fight():    
    player_wins = 0
    alien_wins = 0

    while player_wins <= 3 and alien_wins <= 3:    
        player_roll = random.randint(0, 10)
        alien_roll = random.randint(0, 7)

        if player_roll > alien_roll:
            contents.set("You manage to fire a shot of your laser pistol and the alien backs off.")
            player_wins += 1
        elif alien_roll > player_roll:
            contents.set("The alien reaches out and strikes you with its claws.")
            alien_wins += 1
        else:
            contents.set("You both grapple eachother and eventually back off.")     

    if player_wins == 3:
        contents.set("You manage to overcome the alien. It leaps from wall to wall and crawls into the vents.")
        win = True
    else:
        contents.set("You lose the fight to the alien. Game Over!")

你也不需要那些break语句，因为它完全打破了循环。您可能正在考虑continue，它将进入循环的下一次迭代，但是即使这样也不需要，因为循环的整个内容只是一个if/else语句，所以只有一个分支将执行。

此外，您检查两个elif相等的rolls是不必要的，因为您已经排除了两者都不大于/小于另一个，因此可以假设它们是等于。同样适用于最终if/else，您可以在其中检查谁3。如果我们不在循环中，我们知道某人有3，所以我们只需要实际检查单个玩家得分。

在循环中使用两个计数器

2 个答案: