Question

这是我的JSON文件。

{"result":[
{"beer":"23","store":"1","table":"1"},
{"beer":"12","store":"1","table":"1"},
{"beer":"5","store":"1","table":"2"}]}

如果商店和桌子字段相同，我想要加啤酒。

结果应该是2条记录：

beer 35, store 1 table 1
beer 5, store 1 table 2

这是我使用的MYSQL查询：

$sql = "SELECT * FROM data  ORDER BY beer DESC";
        $res = mysql_query($sql);
        $result = array();

        while( $row = mysql_fetch_array($res) )
            array_push($result, array('beer' => $row[1],
                                      'store'  => $row[2],
                                      'table' => $row[3]));

        echo json_encode(array("result" => $result));

Answer 1

希望您需要group by

$sql = "
    SELECT sum(beer) as beer, store, table 
    FROM data 
    GROUP BY store, table  
    ORDER BY beer DESC
";

Answer 2

直接从sql执行此操作：

$ query =“选择总和（啤酒）作为啤酒，商店，桌子来自数据 GROUP BY商店，表“;

从json中总结出来：

$json_result = json_decode($json_var) ;

$result = array() ;

foreach($json_result->result as $key=>$value){
    if(!isset($result[$value->store])){
        $result[$value->store] = array() ;
        $result[$value->store][$value->table] = $value->beer ;
    }
    else if(!isset($result[$value->store][$value->table])){
        $result[$value->store][$value->table] = $value->beer ;
    }
    else{
        $result[$value->store][$value->table] += $value->beer ;
    }
}

$result will contain the json sum

如果两个字段使用JSON COUNT - SUM相同，我如何求值

2 个答案: