如何在Swift中检查SendSynchronousRequest中的response.statusCode 守则如下:
let urlPath: String = "URL_IS_HERE"
var url: NSURL = NSURL(string: urlPath)
var request: NSURLRequest = NSURLRequest(URL: url)
var response: AutoreleasingUnsafeMutablePointer<NSURLResponse?> = nil
var error: NSErrorPointer? = nil
var data = NSURLConnection.sendSynchronousRequest(request, returningResponse: response, error: nil) as NSData?
在目标c之前和之后,我们检查response.statusCode用这个: (长)response.statusCode 但在swift中我不知道如何检查响应状态代码
答案 0 :(得分:65)
传入对响应的引用,因此它被填充然后检查结果并将其转换为HTTPResponse,因为只有http响应声明了状态代码属性。
let urlPath: String = "http://www.google.de"
var url: NSURL = NSURL(string: urlPath)
var request: NSURLRequest = NSURLRequest(URL: url)
var response: NSURLResponse?
var data = NSURLConnection.sendSynchronousRequest(request, returningResponse: &response, error: nil) as NSData?
if let httpResponse = response as? NSHTTPURLResponse {
println("error \(httpResponse.statusCode)")
}
注意:在objC中你也会使用相同的方法,但如果使用方括号,编译器不会强制执行强制转换。 Swift(类型安全)确实强制执行强制转换
答案 1 :(得分:52)
@GarySabo的Swift 3版本回答:
let url = URL(string: "https://apple.com")!
let request = URLRequest(url: url)
let task = URLSession.shared().dataTask(with: request) {data, response, error in
if let httpResponse = response as? HTTPURLResponse {
print("statusCode: \(httpResponse.statusCode)")
}
}
task.resume()
答案 2 :(得分:10)
Swift 3 +
let dataURL = "https://myurl.com"
var request = URLRequest(url: URL(string: dataURL)!)
request.addValue("Bearer \(myToken)", forHTTPHeaderField: "Authorization")
URLSession.shared.dataTask(with: request) { (data, response, error) in
// Check if the response has an error
if error != nil{
print("Error \(String(describing: error))")
return
}
if let httpResponse = response as? HTTPURLResponse{
if httpResponse.statusCode == 401{
print("Refresh token...")
return
}
}
// Get data success
}.resume()
答案 3 :(得分:7)
我使用URLResponse的扩展来简化这个(Swift 3):
extension URLResponse {
func getStatusCode() -> Int? {
if let httpResponse = self as? HTTPURLResponse {
return httpResponse.statusCode
}
return nil
}
}
答案 4 :(得分:6)
使用NSURLSession清理Swift 2.0
let urlPath: String = "http://www.google.de"
let url: NSURL = NSURL(string: urlPath)!
let request: NSURLRequest = NSURLRequest(URL: url)
var response: NSURLResponse?
let session = NSURLSession.sharedSession()
let task = session.dataTaskWithRequest(request) {urlData, response, reponseError in
if let httpResponse = response as? NSHTTPURLResponse {
print("error \(httpResponse.statusCode)")
}
}
task.resume()
//You should not write any code after `task.resume()`
答案 5 :(得分:2)
如果您使用Just库,它就像:
一样简单Just.get("URL_IS_HERE").statusCode
答案 6 :(得分:0)
创建扩展程序以检查有效/无效的响应-
extension HTTPURLResponse {
func isResponseOK() -> Bool {
return (200...299).contains(self.statusCode)
}
}
获取请求的响应-
let task = URLSession.shared.dataTask(with: request) { (jsonData, response, error) in
// post result on main thread
DispatchQueue.main.async {
if let response = response as? HTTPURLResponse, response.isResponseOK() {
// assume if we don't receive any error then its successful
handler(true)
} else {
handler(false)
}
}
}
task.resume()
}