Question

我想将字符串中的值组合在一起。例如，

Let A = a,b,c,d

我希望组合为，

AComb = a,b,c,d,ab,ac,ad,bc,bd,cd,abc,abd,bcd,acd

Answer 1

我假设A是Set

scala> val A =Set("a","b","c","d")
A: scala.collection.immutable.Set[String] = Set(a, b, c, d)


scala> val AComb=A.toSet[String].subsets.map(_.mkString).toVector
AComb: Vector[String] = Vector("", a, b, c, d, ab, ac, ad, bc, bd, cd, abc, abd, acd, bcd, abcd)

我认为你并不需要第一个元素，所以你可以尝试

scala> val AComb=A.toSet[String].subsets.map(_.mkString).toVector.tail
AComb: scala.collection.immutable.Vector[String] = Vector(a, b, c, d, ab, ac, ad, bc, bd, cd, abc, abd, acd, bcd, abcd)

删除第一个和最后一个元素

scala> val AComb=A.toSet[String].subsets.map(_.mkString).toVector.init.tail
AComb: scala.collection.immutable.Vector[String] = Vector(a, b, c, d, ab, ac, ad, bc, bd, cd, abc, abd, acd, bcd)

根据评论更新

scala> val xc1=Set("sunny","hot","high","FALSE","no")
xc1: scala.collection.immutable.Set[String] = Set(sunny, FALSE, hot, no, high)

scala> val AComb=xc1.toSet[String].subsets.map(_.mkString(" ")).toVector.tail;
AComb: scala.collection.immutable.Vector[String] = Vector(sunny, FALSE, hot, no, high, sunny FALSE, sunny hot, sunny no, sunny high, FALSE hot, FALSE no, FALSE high, hot no, hot high, no high, sunny FALSE hot, sunny FALSE no, sunny FALSE high, sunny hot no, sunny hot high, sunny no high, FALSE hot no, FALSE hot high, FALSE no high, hot no high, sunny FALSE hot no, sunny FALSE hot high, sunny FALSE no high, sunny hot no high, FALSE hot no high)

如何使用scala在字符串中组合值？

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