尝试添加已经拥有父级的SKNode - Swift

时间:2014-10-04 00:26:29

标签: swift sprite-kit sknode

确定。这段代码让我抓狂。它只是不起作用。我收到的唯一消息是"尝试添加已经拥有父母"的SKNode。是的我知道这里有一些讨论,但没有一个能提供我需要的解决方案。

这是代码。我真的很感激任何帮助。

import SpriteKit

class MyScene: SKScene {

  let intervalShapeCreation:NSTimeInterval = 2.0  // Interval for creating the next Shape
  let gravitationalAcceleration:CGFloat = -0.5    // The gravitational Y acceleration

  let shapeSequenceAction = SKAction.sequence([
    SKAction.scaleTo(1.0, duration: 0.5),
    SKAction.waitForDuration(2.0),
    SKAction.scaleTo(0, duration: 0.5),
    SKAction.removeFromParent()
    ])

  override init(size: CGSize) {
    super.init(size: size)
  }

  required init(coder aDecoder: NSCoder) {
    super.init(coder: aDecoder)
  }

  override func didMoveToView(view: SKView) {
    super.didMoveToView(view)
    addBackground()
    initializeScene()
  }

  // MARK: Level Building
  func initializeScene() {
    self.physicsWorld.gravity = CGVectorMake(0.0, gravitationalAcceleration)
    runAction(SKAction.repeatActionForever(
      SKAction.sequence([SKAction.runBlock(self.createShape),
      SKAction.waitForDuration(intervalShapeCreation)])))
  }

  func addBackground() {
    let backgroundAtlas = SKTextureAtlas(named: "background")
    let background = SKSpriteNode(texture: backgroundAtlas.textureNamed("background"))
    background.position = CGPoint(x: size.width/2, y: size.height/2)
    background.anchorPoint = CGPointMake(0.5, 0.5)
    background.zPosition = -1
    background.name = "background"
    self.addChild(background)
  }

  func createShape() {
    let newShape = sSharedAllPossibleShapes[0]
    print("\n shape creada: \(newShape.name)")
    newShape.position = CGPointMake(size.width / 2, CGFloat( Int.random(fromZeroToMax: 500)))
    self.addChild(newShape)
    newShape.runAction(shapeSequenceAction)
  }

}

1 个答案:

答案 0 :(得分:1)

createShape实际上并没有创建SKShapeNode。它从sSharedAllPossibleShapes数组中获取第一个形状,然后将其作为子项添加到self中。第二次调用此方法时,形状已经有父级,无法再次添加。

您必须创建SKShapeNode的新实例。我在这里看到你的数组的方式确实需要包含定义形状的CGPath对象,而不是节点本身,因为你不能按照你想要的方式重用节点。