我试图获得两个日期之间的时间,但它似乎没有给我正确的结果。
global $wpdb;
global $wp;
$wp->query_vars['sp_date'] = "10/06/2014";
$wp->query_vars['sp_time_period'] = "2pm to 3pm";
// only process requests with "my-plugin=ajax-handler"
date_default_timezone_set('America/New_York');
$date = false;
$time_span = false;
$dayoffs = false;
if(isset($wp->query_vars['sp_date'])) {
$date = $wp->query_vars['sp_date'];
}
if(isset($wp->query_vars['sp_time_period'])) {
$period = $wp->query_vars['sp_time_period'];
}
if(isset($wp->query_vars['get_dayoffs'])) {
$dayoffs = $wp->query_vars['get_dayoffs'];
}
$returnValue = 0;
if($date || $period) {
$hrs = 0;
if($date && !$returnValue) {
$_SESSION['sp_date'] = $date;
$returnValue = 1;
}
if($period && !$returnValue) {
$_SESSION['sp_time_period'] = $period;
$returnValue = 1;
}
if($_SESSION['sp_date']) {
$hrsTilNoonBool = 0;
$nToday = date("Y-m-d h:i:s");
$deliveryDates = $_SESSION['sp_date']." 18:00:00";
$deliveryDateNoon = $_SESSION['sp_date']." 12:00:00";
$date1 = new DateTime($nToday);
$date2 = new DateTime($deliveryDates);
$date3 = new DateTime($deliveryDateNoon);
$diff = $date2->diff($date1);
$diffNoon = $date3->diff($date1);
$hrs = $diff->format('%H');
$hrsTilNoon = $diffNoon->format('%h');
if($hrsTilNoon) {
$hrsTilNoonBool = 1;
}
}
$settings = $wpdb->get_results("SELECT * FROM sp_settings WHERE id = 1");
$content = '{"value":'.$returnValue.', "over_twentyfour":'.$hrs;
if(!$settings[0]->payment_id_before)
$settings[0]->payment_id_before = 53;
if(!$settings[0]->payment_id_after)
$settings[0]->payment_id_after = 54;
$content .= ',"payment_before":'.$settings[0]->payment_id_before.',"payment_after":'.$settings[0]->payment_id_after.',"before_afternoon":'.
$hrsTilNoonBool.'}';
}
if($dayoffs) {
$dates = $wpdb->get_results("SELECT * FROM sp_date_blacklist");
$datesArry = array();
foreach($dates as $d) {
$datesArry[] = $d->date;
}
$content = json_encode($datesArry);
}
echo $content;
exit();
我首先输入目标日期$wp->query_vars['sp_date'] = "10/06/2014";
然后我今天的日期是10/03/2014。
$diff = $date2->diff($date1);
$diffNoon = $date3->diff($date1);
$hrs = $diff->format('%H');
日子说3是对的。但是时间是14小时?我很迷惑。也许我可能没有正确阅读
答案 0 :(得分:1)
尝试将相同的时间附加到每个时间戳,例如'00:00:00'。当你今天的日期,它也需要当前的时间。默认情况下,创建日期为午夜。
答案 1 :(得分:1)
你在模棱两可的日子里收费:
$d1 = '01/02/2013';
$d2 = '01-02-2013';
$ts1 = strtotime($d1); // 1357106400
$ts2 = strtotime($d2); // 1359698400
echo date('r', $ts1); // Wed, 02 Jan 2013 00:00:00 -0600
echo date('r', $ts2); // Fri, 01 Feb 2013 00:00:00 -0600
/
v。 strtotime中的-
分隔符()会产生重大影响。这是欧洲的dd-mm-yyyy v.s.美国mm / dd / yyyy
您应该使用date_create_from_format()和EXCPLICITLY指定输入日期字符串的格式。