Question

我有一个12小时的时钟来计算两次十进制之间的差异。它运行在下面的循环中，但经过测试后，我看到当我输入介于12:00和12:59（上午或下午）之间的时间时，它会发布完全错误的时间。问题是第12小时是特殊情况，不需要添加或减去12小时。我如何解决这个问题，以便以十进制的形式发布正确的时间？

此外，由于我发布这个，我有另一个问题;如何轻松计算十进制的总时间？

这是GUI的图片，因此您可以了解我们正在处理的内容。 http://imgur.com/y7JezcC

protected void CalculateButton_Click(object sender, EventArgs e)
{
    //Initializing
    TextBox[] textboxesIn = new TextBox[7];
    TextBox[] textboxesOut = new TextBox[7];
    DropDownList[] dropdownIn = new DropDownList[7];
    DropDownList[] dropdownOut = new DropDownList[7];
    Label[] labels = new Label[7];

    //Week 1 in textboxes
    textboxesIn[0] = MondayW1InTextBox;
    textboxesIn[1] = TuesdayW1InTextBox;
    textboxesIn[2] = WednesdayW1InTextBox;
    textboxesIn[3] = ThursdayW1InTextBox;
    textboxesIn[4] = FridayW1InTextBox;
    textboxesIn[5] = SaturdayW1InTextBox;
    textboxesIn[6] = SundayW1InTextBox;

    //Week 1 out textboxes
    textboxesOut[0] = MondayW1OutTextBox;
    textboxesOut[1] = TuesdayW1OutTextBox;
    textboxesOut[2] = WednesdayW1OutTextBox;
    textboxesOut[3] = ThursdayW1OutTextBox;
    textboxesOut[4] = FridayW1OutTextBox;
    textboxesOut[5] = SaturdayW1OutTextBox;
    textboxesOut[6] = SundayW1OutTextBox;

    //Week 1 in drop down list
    dropdownIn[0] = MondayW1InDropDown;
    dropdownIn[1] = TuesdayW1InDropDown;
    dropdownIn[2] = WednesdayW1InDropDown;
    dropdownIn[3] = ThursdayW1InDropDown;
    dropdownIn[4] = FridayW1InDropDown;
    dropdownIn[5] = SaturdayW1InDropDown;
    dropdownIn[6] = SundayW1InDropDown;

    //Week 1 out drop down list
    dropdownOut[0] = MondayW1OutDropDown;
    dropdownOut[1] = TuesdayW1OutDropDown;
    dropdownOut[2] = WednesdayW1OutDropDown;
    dropdownOut[3] = ThursdayW1OutDropDown;
    dropdownOut[4] = FridayW1OutDropDown;
    dropdownOut[5] = SaturdayW1OutDropDown;
    dropdownOut[6] = SundayW1OutDropDown;

    //Week 1 labels
    labels[0] = MondayW1Label;
    labels[1] = TuesdayW1Label;
    labels[2] = WednesdayW1Label;
    labels[3] = ThursdayW1Label;
    labels[4] = FridayW1Label;
    labels[5] = SaturdayW1Label;
    labels[6] = SundayW1Label;

    for (int i = 0; i < 7; i++)
    {
        DateTime dt = DateTime.ParseExact(textboxesIn[i].Text.PadLeft(4, '0'), "HHmm", CultureInfo.InvariantCulture);
        string timestring = dt.ToString("h:mm");
        labels[i].Text = timestring;

        DateTime timeIn = DateTime.ParseExact(textboxesIn[i].Text.PadLeft(4, '0'), "HHmm", CultureInfo.InvariantCulture);
        DateTime timeOut = DateTime.ParseExact(textboxesOut[i].Text.PadLeft(4, '0'), "HHmm", CultureInfo.InvariantCulture);

        if (dropdownIn[i].SelectedValue == "PM")
        {
            timeIn = timeIn.AddHours(12);
        }

        if (dropdownOut[i].SelectedValue == "PM")
        {
            timeOut = timeOut.AddHours(12);
        }
        labels[i].Text = (timeOut - timeIn).TotalHours.ToString("f2");
    }
}

Answer 1

尝试

DateTime timeIn = DateTime.ParseExact(textboxesIn[i].Text.PadLeft(4, '0') + dropdownIn[i].SelectedValue.Text, "hhmm tt", CultureInfo.InvariantCulture);

您必须将HH更改为hh，因为您无法将12AM解析为HH。之后你可以在没有问题的情况下使用timeOut - time。

Answer 2

在每种情况下，当你写1到11时，它默认为AM，你可以总和12 hs，但是当你写12时总是PM（AM将是00），所以：

1PM + 12 = 13

2PM + 12 = 14

...

晚上11点+12 = 23

//现在你的奇怪结果：

12:45（PM）+12 = 24:45 =＆gt; 00:45但是后一天

3:00（PM）+ 12 = 15

15hs（第0天） - 00:45（第1天）是你的负面结果。

当12岁时，一个简单的方法是休息12小时。

for (int i = 0; i < 7; i++)
    {
        DateTime dt = DateTime.ParseExact(textboxesIn[i].Text.PadLeft(4, '0'), "HHmm", CultureInfo.InvariantCulture);
        string timestring = dt.ToString("h:mm");
        labels[i].Text = timestring;

        DateTime timeIn = DateTime.ParseExact(textboxesIn[i].Text.PadLeft(4, '0'), "HHmm", CultureInfo.InvariantCulture);
        DateTime timeOut = DateTime.ParseExact(textboxesOut[i].Text.PadLeft(4, '0'), "HHmm", CultureInfo.InvariantCulture);

        if(timeIn.Hour == 12) timeIn = timeIn.AddHours(-12);  //a easy way

        if (dropdownIn[i].SelectedValue == "PM")
        {
            timeIn = timeIn.AddHours(12);
        }

        if (dropdownOut[i].SelectedValue == "PM")
        {
            timeOut = timeOut.AddHours(12);
        }
        labels[i].Text = (timeOut - timeIn).TotalHours.ToString("f2");
    }

12小时制，十二小时制

2 个答案: