想象一下这样的网络设置:
+---------+ +---------+
| (1)+---------------+(2) |
| host1 | | host2 |
| | | |
| (3)+---------------+(4) |
+---------+ +---------+
其中1,2,3,4是网络接口。两个接口之间的线路表示存在(路由)连接。现在,当我设置客户端和服务器时,将服务器绑定到IP地址4,客户端绑定到1我仍然可以建立连接,因为host1的传出流量将通过接口3路由。
以下代码不是我的实际程序,而是来自a tutorial的示例代码。我稍微修改了一下。它仅用于显示一些不像我希望它表现的工作代码。
server.c
/* A simple server in the internet domain using TCP
The port number is passed as an argument */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#include <sys/types.h>
#include <sys/socket.h>
#include <netinet/in.h>
#include <arpa/inet.h>
void error(const char *msg)
{
perror(msg);
exit(1);
}
int main(int argc, char *argv[])
{
int sockfd, newsockfd, portno;
socklen_t clilen;
char buffer[256];
struct sockaddr_in serv_addr, cli_addr;
int n;
if (argc < 2) {
fprintf(stderr,"ERROR, no port provided\n");
exit(1);
}
sockfd = socket(AF_INET, SOCK_STREAM, 0);
if (sockfd < 0)
error("ERROR opening socket");
bzero((char *) &serv_addr, sizeof(serv_addr));
portno = atoi(argv[1]);
serv_addr.sin_family = AF_INET;
inet_aton(argv[2], &serv_addr.sin_addr);
serv_addr.sin_port = htons(portno);
if (bind(sockfd, (struct sockaddr *) &serv_addr,
sizeof(serv_addr)) < 0)
error("ERROR on binding");
listen(sockfd,5);
clilen = sizeof(cli_addr);
newsockfd = accept(sockfd,
(struct sockaddr *) &cli_addr,
&clilen);
if (newsockfd < 0)
error("ERROR on accept");
bzero(buffer,256);
n = read(newsockfd,buffer,255);
if (n < 0) error("ERROR reading from socket");
printf("Here is the message: %s\n",buffer);
n = write(newsockfd,"I got your message",18);
if (n < 0) error("ERROR writing to socket");
close(newsockfd);
close(sockfd);
return 0;
}
client.c
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <string.h>
#include <sys/types.h>
#include <sys/socket.h>
#include <netinet/in.h>
#include <netdb.h>
#include <arpa/inet.h>
void error(const char *msg)
{
perror(msg);
exit(0);
}
int main(int argc, char *argv[])
{
int sockfd, portno, n;
struct sockaddr_in serv_addr, client_addr;
struct hostent *server;
char buffer[256];
if (argc < 3) {
fprintf(stderr,"usage %s hostname port\n", argv[0]);
exit(0);
}
portno = atoi(argv[2]);
sockfd = socket(AF_INET, SOCK_STREAM, 0);
if (sockfd < 0)
error("ERROR opening socket");
server = gethostbyname(argv[1]);
if (server == NULL) {
fprintf(stderr,"ERROR, no such host\n");
exit(0);
}
bzero((char *) &serv_addr, sizeof(serv_addr));
serv_addr.sin_family = AF_INET;
bcopy((char *)server->h_addr,
(char *)&serv_addr.sin_addr.s_addr,
server->h_length);
serv_addr.sin_port = htons(portno);
client_addr.sin_family = AF_INET;
inet_aton(argv[3], &client_addr.sin_addr);
client_addr.sin_port = htons(portno);
if (bind(sockfd, (struct sockaddr *) &client_addr,
sizeof(client_addr)) < 0)
error("ERROR on binding");
if (connect(sockfd,(struct sockaddr *) &serv_addr,sizeof(serv_addr)) < 0)
error("ERROR connecting");
printf("Please enter the message: ");
bzero(buffer,256);
fgets(buffer,255,stdin);
n = write(sockfd,buffer,strlen(buffer));
if (n < 0)
error("ERROR writing to socket");
bzero(buffer,256);
n = read(sockfd,buffer,255);
if (n < 0)
error("ERROR reading from socket");
printf("%s\n",buffer);
close(sockfd);
return 0;
}
我想要的是流量仅从1流向2(反之亦然),从3流向4流(或反之亦然)。理想地尝试从例如建立连接1到4应该失败,因为没有路线。
我无法修改任何主机的路由表(或者只能为我的进程更改它?)。 我已经尝试SO_BINDTODEVICE了。一般来说,这就是我想要的,即流量然后流过1和4.然而,它确实不会避免建立1和4之间的连接。后者不是一个要求,但会很高兴。不幸的是,SO_BINDTODEVICE在OSX上不可用,我找不到任何类似的套接字选项。
int bind_to_if(int fd, const char * const if_name)
{
struct ifreq interface;
memset(&interface, 0, sizeof(interface));
strncpy(interface.ifr_name, if_name, IFNAMSIZ);
if(setsockopt(fd, SOL_SOCKET, SO_BINDTODEVICE, &interface, sizeof(struct ifreq))) {
return -1;
}
return0;
}
我的代码需要在Linux,FreeBSD和OSX下运行。如果无法避免,有些ifdef是可以接受的。