我有以下情况。
消息来源表1
CREATE TABLE #Table1
(
Div varchar(10),
Dept varchar(10),
States varchar(10)
)
INSERT INTO #Table1
SELECT 'Div1','Dept1','CA,NV,TX'
UNION ALL
SELECT 'Div2','Dept2','MI,OH,IN'
UNION ALL
SELECT 'Div3','Dept2','NY,NJ,PA'
UNION ALL
SELECT 'Div4','Dept1',NULL
消息来源表2
CREATE TABLE #Table2
(
Div varchar(10),
Dept varchar(10),
States varchar(10)
)
INSERT INTO #Table2
SELECT 'Div1','Dept1','CA'
UNION ALL
SELECT 'Div1','Dept1','NV, TX'
UNION ALL
SELECT 'Div1','Dept1','TX, CA'
UNION ALL
SELECT 'Div1','Dept1','CA, NV'
UNION ALL
SELECT 'Div2','Dept2','MI, OH'
UNION ALL
SELECT 'Div2','Dept2','MI, IN'
UNION ALL
SELECT 'Div2','Dept2','OH'
UNION ALL
SELECT 'Div3','Dept2','NY, NJ, PA'
渴望输出
CREATE TABLE #Table3
(
Div varchar(10),
Dept varchar(10),
States varchar(50)
)
INSERT INTO #Table3
SELECT 'Div1','Dept1','CA - (3), NV - (2), TX - (2)'
UNION ALL
SELECT 'Div2','Dept2','MI - (2), OH - (2), IN - (1)'
UNION ALL
SELECT 'Div3','Dept2','NY - (1), NJ - (1), PA - (1)'
UNION ALL
SELECT 'Div4','Dept1',NULL
SELECT * FROM #Table1
SELECT * FROM #Table2
SELECT * FROM #Table3
DROP TABLE #Table1
DROP TABLE #Table2
DROP TABLE #Table3
目标：根据#Table1和#Table2，加入Div和Dept字段中的两个表，然后汇总States字段中不同状态的计数并创建一个输出，其中Div，Dept和States具有该州旁边打印的每个状态的唯一计数。
我不知道如何实现这一目标。我正在尝试LIKE，但无法弄清楚如何让它变得动态。我会继续试着看看能不能搞清楚。以为我会在这里发布这个问题，看看能否得到一些帮助。
谢谢
更新：
期望输出
Div Dept States
Div1 Dept1 CA - (3), NV - (2), TX - (2)
Div2 Dept2 MI - (2), OH - (2), IN - (1)
Div3 Dept2 NY - (1), NJ - (1), PA - (1)
Div4 Dept1 NULL
答案 0 :(得分：6)
好的，首先，您需要在#Temp1和#Temp2中拆分连接值。这样做的方法有很多种，我将使用来自Aaron Bertrand的in this awesome blog描述的数字表。所以，我们需要一个数字表，可以这样做：
;WITH n AS
(
SELECT x = ROW_NUMBER() OVER (ORDER BY s1.[object_id])
FROM sys.all_objects AS s1
CROSS JOIN sys.all_objects AS s2
)
SELECT Number = x
INTO #Numbers
FROM n
WHERE x BETWEEN 1 AND 8000;
然后，你需要实际进行拆分，然后为你的结果进行组连接方法：
;WITH T1 AS
(
SELECT *
FROM #Table1 T
OUTER APPLY (SELECT Item = SUBSTRING(T.States, Number,
CHARINDEX(',',T.States + ',', Number) -
Number)
FROM #Numbers
WHERE Number <= CONVERT(INT, LEN(T.States))
AND SUBSTRING(',' + T.States, Number, LEN(',')) = ',') N
), T2 AS
(
SELECT *
FROM #Table2 T
OUTER APPLY (SELECT Item = SUBSTRING(T.States, Number,
CHARINDEX(', ',T.States + ', ', Number) -
Number)
FROM #Numbers
WHERE Number <= CONVERT(INT, LEN(T.States))
AND SUBSTRING(', ' + T.States, Number, LEN(', ')) = ', ') N
), T3 AS
(
SELECT T1.Div, T1.Dept, T1.Item, COUNT(*) N
FROM T1
LEFT JOIN T2
ON T1.Div = T2.Div
AND T1.Dept = T2.Dept
AND T1.Item = T2.Item
GROUP BY T1.Div, T1.Dept, T1.Item
)
SELECT A.Div,
A.Dept,
States = STUFF((SELECT ',' + CONVERT(VARCHAR(20), Item) +
' - (' + CAST(N AS VARCHAR(4)) + ')'
FROM T3
WHERE Div = A.Div
AND Dept = A.Dept
FOR XML PATH(''), TYPE).value('.[1]','nvarchar(max)'),1,1,'')
FROM T3 A
ORDER BY Div, Dept, Item
结果是：
╔══════╦═══════╦════════════════════════════╗
║ Div ║ Dept ║ States ║
╠══════╬═══════╬════════════════════════════╣
║ Div1 ║ Dept1 ║ CA - (3),NV - (2),TX - (2) ║
║ Div1 ║ Dept1 ║ CA - (3),NV - (2),TX - (2) ║
║ Div1 ║ Dept1 ║ CA - (3),NV - (2),TX - (2) ║
║ Div2 ║ Dept2 ║ IN - (1),MI - (2),OH - (2) ║
║ Div2 ║ Dept2 ║ IN - (1),MI - (2),OH - (2) ║
║ Div2 ║ Dept2 ║ IN - (1),MI - (2),OH - (2) ║
║ Div3 ║ Dept2 ║ NJ - (1),NY - (1),PA - (1) ║
║ Div3 ║ Dept2 ║ NJ - (1),NY - (1),PA - (1) ║
║ Div3 ║ Dept2 ║ NJ - (1),NY - (1),PA - (1) ║
║ Div4 ║ Dept1 ║ NULL ║
╚══════╩═══════╩════════════════════════════╝
答案 1 :(得分：6)
您的要求非常恶劣，但作为开发人员，我们必须使用我们所拥有的。这是一个广泛使用公用表表达式（CTE）的解决方案：
;WITH
CTE1 AS
(
SELECT Div, Dept,
REPLACE(States,' ','') + ',' AS States
FROM Table2
),
CTE2 AS
(
SELECT c1.Div, c1.Dept,
LEFT(c1.States,CHARINDEX(',', c1.States)-1) AS IndividualState,
RIGHT(c1.States,LEN(c1.States)-CHARINDEX(',', c1.States)) AS RemainingStates
FROM CTE1 c1
UNION ALL
SELECT c2.Div, c2.Dept,
LEFT(c2.RemainingStates,CHARINDEX(',', c2.RemainingStates)-1),
RIGHT(c2.RemainingStates,LEN(c2.RemainingStates) - CHARINDEX(',', c2.RemainingStates))
FROM CTE2 c2
WHERE LEN(c2.RemainingStates) > 0
),
CTE3 AS
(
SELECT Div, Dept,
IndividualState,
COUNT(*) AS StateCount
FROM CTE2
GROUP BY Div, Dept, IndividualState
),
CTE4 AS
(
SELECT t1.Div, t1.Dept,
(
SELECT c3.IndividualState + ' - (' + CONVERT(varchar(10),c3.StateCount) + '), '
FROM CTE3 c3
WHERE c3.Div = t1.Div AND c3.Dept = t1.Dept
FOR XML PATH('')
) AS States
FROM Table1 t1
)
SELECT Div, Dept,
LEFT(States, LEN(States) - 1) AS States
FROM CTE4
CTE1清除Table2中的数据：删除空格，在末尾添加逗号CTE2进行规范化CTE3进行计数CTE4执行最终程序集，将CA | 3放入CA - (3), ... 最后SELECT删除整数输出的尾随逗号。
为了更好地理解每个步骤，您可以将最终的SELECT替换为SELECT * FROM CTE1，SELECT * FROM CTE2等。
答案 2 :(得分：2)
理想情况下，这些数据当然会被标准化，因为这很麻烦。鉴于您已经坚持使用此结构，我认为您最好的选择是使用状态驱动程序表或使用可用的许多拆分函数之一来拆分分隔值，然后使用它来获取每个陈述自己的路线：
;WITH cte AS (SELECT DISTINCT b.Div,b.Dept,a.abbrs
FROM #States a
RIGHT JOIN #Table1 b
ON ','+REPLACE(b.States,' ','')+',' LIKE '%,'+a.abbrs+',%'
)
,cte2 AS (SELECT b.Div,b.Dept,a.abbrs
FROM #States a
JOIN #Table2 b
ON ','+REPLACE(b.States,' ','')+',' LIKE '%,'+a.abbrs+',%'
)
,cte3 AS (SELECT a.Div,a.Dept,a.abbrs,CAST(COUNT(b.abbrs)AS VARCHAR(25)) CT
FROM cte a
LEFT JOIN cte2 b
ON a.Dept = b.Dept
AND a.Div = b.Div
AND a.abbrs = b.abbrs
GROUP BY a.div,a.dept,a.abbrs
)
SELECT DISTINCT
Div,Dept
,STUFF((SELECT DISTINCT ',' + abbrs+'-('+CT+')'
FROM cte3 b
WHERE a.Div = b.Div
AND a.Dept = b.Dept
FOR XML PATH(''), TYPE).value('.', 'VARCHAR(MAX)')
,1,1,'')
FROM cte3 a
演示：SQL Fiddle
注意：
输出是：
| DIV | DEPT | STATES |
|------|-------|----------------------|
| Div1 | Dept1 | CA-(3),NV-(2),TX-(2) |
| Div2 | Dept2 | IN-(1),MI-(2),OH-(2) |
| Div3 | Dept2 | NJ-(1),NY-(1),PA-(1) |
| Div4 | Dept1 | (null) |
更新了小提琴以包含您的NULL行并添加了输出。