Sendgrid - PHP - 将json数据发布到我的数据库

时间:2014-10-03 16:23:57

标签: php json curl sendgrid

我正在尝试使用以下代码通过curl命令连接到sendgrid,并使用foreach将结果发布到我的数据库。现在我的用户名和密码上的未定义索引错误,以及我的foreach上的无效参数。我相信我知道为什么我得到了foreach错误,我在代码中对它进行了评论,但我不确定通过web api的连接方面。感谢

*编辑 - 我想添加我的端点已设置,我可以通过ngroks web界面查看测试数据。

<?php

require_once('../functions.php');
session_start();
connect();

//Enable Connection to Event Notifications
    $url = 'https://api.sendgrid.com/';
    $user = $_SESSION["xxxxxxx"];
    $pass = $_SESSION["xxxxxxx"];
    $params = array(
        'api_user' => $user,
        'api_key' => $pass,
        'name' => 'eventnotify' //API App Name
    );
    $request = $url . 'api/filter.activate.json'; //i believe the [module] and [action] is incorrect here.

// Generate first curl request
    $session = curl_init($request);

// Tell curl to use HTTP POST
    curl_setopt($session, CURLOPT_POST, true);

// Tell curl that this is the body of the POST
    curl_setopt($session, CURLOPT_POSTFIELDS, $params);

// Tell curl not to return headers, but do return the response
    curl_setopt($session, CURLOPT_HEADER, false);
    curl_setopt($session, CURLOPT_RETURNTRANSFER, true);

// obtain response
    $response = curl_exec($session);
    curl_close($session);


    $data = $response[file_get_contents("php://input")]; // Can i do this? Or do i just pass a $json variable?
    $records = json_decode($data, true);

    foreach ($records as $record) {
        // Here, you now have each event and can process them how you like
        echo getArray($record);
        $email = isset($record['email']) ? $record['email'] : null;
        $event = $record['event'];

        $uid = $_POST['uid'];
        $timestamp = $_POST['timestamp'];
        $event_type = $_POST['event'];
        $email_address = $_POST['email'];
        $smtpid = $_POST['smtpid'];
        $sg_event_id = $_POST['sg_event_id'];
        $sg_message_id = $_POST['sg_message_id'];
        $category = $_POST['category'];
        $newsletter = $_POST['newsletter'];
        $response = $_POST['response'];
        $reason = $_POST['reason'];
        $ip = $_POST['ip'];
        $useragent = $_POST['useragent'];
        $attempt = $_POST['attempt'];
        $status = $_POST['status'];
        $type = $_POST['type'];
        $url = $_POST['url'];
        $additional_arguments = $_POST['additional_arguements'];
        $event_post_timestamp = $_POST['event_post_timestamp'];
        $raw = $_POST['raw'];
        $customer_id = $_POST['customer_id'];

        insert("sendgrid_events", array("uid" => $uid,
            "timestamp" => $timestamp,
            "event" => $event_type,
            "email" => $email_address,
            "smtpid" => $smtpid,
            "sg_event_id" => $sg_event_id,
            "sg_message_id" => $sg_message_id,
            "category" => $category,
            "newsletter" => $newsletter,
            "response" => $response,
            "reason" => $reason,
            "ip" => $ip,
            "useragent" => $useragent,
            "attempt" => $attempt,
            "status" => $status,
            "type" => $type,
            "url" => $url,
            "additional_arguments" => $additional_arguments,
            "event_post_timestamp" => $event_post_timestamp,
            "raw" => $raw,
            "customer_id" => $customer_id)); //Unique Arguement to attach customer id on original outbound email? Yes
    }

还是非常新的PHP,所以感谢你的帮助。

响应响应:在json_decode函数处理之后,是以数组形式从sendgid发布的POST数据吗?我仍然不太确定我做错了什么。我已将我的代码修改为以下内容,并且我在foreach之外的所有变量上获得了一个未定义的索引,并且对foreach本身进行了无效的争论......

<?php

require_once('../functions.php');
connect();

    $data = file_get_contents("php://input"); // Can i do this? Or do i just pass a $json variable?
    $records = json_decode($data, true);

    $uid = $_POST['uid'];
    $timestamp = $_POST['timestamp'];
    $event_type = $_POST['event'];
    $email_address = $_POST['email'];
    $smtpid = $_POST['smtpid'];
    $sg_event_id = $_POST['sg_event_id'];
    $sg_message_id = $_POST['sg_message_id'];
    $category = $_POST['category'];
    $newsletter = $_POST['newsletter'];
    $response = $_POST['response'];
    $reason = $_POST['reason'];
    $ip = $_POST['ip'];
    $useragent = $_POST['useragent'];
    $attempt = $_POST['attempt'];
    $status = $_POST['status'];
    $type = $_POST['type'];
    $url = $_POST['url'];
    $additional_arguments = $_POST['additional_arguments'];
    $event_post_timestamp = $_POST['event_post_timestamp'];
    $raw = $_POST['raw'];
    $customer_id = $_POST['customer_id'];

    foreach ($records as $record) {

        insert("sendgrid_events", array("uid" => $uid,
                                        "timestamp" => $timestamp,
                                        "event" => $event_type,
                                        "email" => $email_address,
                                        "smtpid" => $smtpid,
                                        "sg_event_id" => $sg_event_id,
                                        "sg_message_id" => $sg_message_id,
                                        "category" => $category,
                                        "newsletter" => $newsletter,
                                        "response" => $response,
                                        "reason" => $reason,
                                        "ip" => $ip,
                                        "useragent" => $useragent,
                                        "attempt" => $attempt,
                                        "status" => $status,
                                        "type" => $type,
                                        "url" => $url,
                                        "additional_arguments" => $additional_arguments,
                                        "event_post_timestamp" => $event_post_timestamp,
                                        "raw" => $raw,
                                        "customer_id" => $customer_id)); //Unique Arguement to attach customer id on original outbound email? Yes
    }

    echo "POST Received";

1 个答案:

答案 0 :(得分:1)

看起来你可能会错误地解释Event Webhook的方式。每次事件发生时,webhook POST的数据都会发送到您的端点(在这种情况下,就是您的PHP脚本)(例如某人打开您的电子邮件)。这一切都是实时发生的。 您希望用于获取和存储活动的API。

但是,您的脚本也使用App/Filter Activation Endpoint。此端点打开和关闭Filter(也称为App)的使用。您只需要使用一次,以确保在事件发生时将数据发布到PHP脚本。但是,通过SendGrid's Web Interface激活它可能更容易。有关该应用程序的更多信息以及您可以使用和修改它的方法,请参阅app description page

如果从脚本中删除cURL请求位,则只需从POST请求获取数据并存储即可。通过将脚本更改为以下内容,事情应该有效:

<?php

// All your boilerplate code
require_once('../functions.php');
connect();

// Get the raw POSTed data
$data = file_get_contents("php://input");

// Decode said data
$records = json_decode($data, true);

// Loop through the records
foreach ($records as $record) {
    // Store the event
    // Assume store_event does your data processing and inserting
    store_event($record);

    // You should be able to access any parameter of the event as so
    // $record["email"];
    // e.g.

    echo $record["email"];
    echo " had an email ";
    echo $record["event"];
}

您的错误位于以下行,您在设置过滤器时尝试将输入POST作为API响应的关键字。由于它不存在,因此数据未定义,因此无法与foreach进行迭代。

// The "bad" code
$data = $response[file_get_contents("php://input")];

您可以看到working code example of the event webhook on SendGrid's Documentation