Question

好的，所以我正在尝试创建我自己的应用程序，它接受您键入的文本，然后将其转换为我已编写的其他语言，如何在EditText中搜索第一个字母然后更改它，然后继续这样做用户输入多长时间？

我是编程的新手，所以如果它很简单，我很抱歉，我没有与数组有关吗？

public class MainMenu extends Activity {
    Button PasswordSetup;
    boolean ShowPasswordBTN = false;
    EditText UserInput,UserOutput;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        this.requestWindowFeature(Window.FEATURE_NO_TITLE);
        setContentView(R.layout.mainmenu);

        PasswordSetup = (Button) findViewById(R.id.SetUpPassword);
        UserInput = (EditText) findViewById(R.id.UserInput);
        //What the user types
        UserOutput = (EditText) findViewById(R.id.UserOutput);
        //What i whnt it toshow in after converting the text

        SharedPreferences GetPasswordBTN = getSharedPreferences("#.#.#.#", Context.MODE_PRIVATE);
        ShowPasswordBTN = GetPasswordBTN.getBoolean("PasswordPres",false);

        if(ShowPasswordBTN==true){
           PasswordSetup.setVisibility(View.GONE);
        }

        UserInput.getText();
           //I want to do it here

        PasswordSetup.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                Intent GoToPasswordSetup = new Intent(getApplicationContext(),PasswordSetup.class);
                startActivity(GoToPasswordSetup);
                finish();
            }
        });
    }
}

这就是我将字母改为

A = CB = DC = ED = FE = GF = HG = IH = JI = KJ = LK = ML = NM = ON = PO = QP = RQ = SR = TS = UT = VU = WV = XW = YX = ZY = BZ = A

Answer 1

您可以在“编辑”文本中添加文本观察程序。

“我如何在EditText中搜索第一个字母然后更改它，然后继续这样做用户输入多长时间？”

 myEditText.addTextChangedListener(new TextWatcher() {
    @Override
    public void onTextChanged(CharSequence s, int start, int before, int count) {
        //check the sequence and do something
    }

    @Override
    public void afterTextChanged(Editable arg0) {
    }

    @Override
    public void beforeTextChanged(CharSequence s, int start, int count, int after) {

    }
});

如何搜索字符串中的字符而不是字符串中的位置然后更改它

1 个答案: