我遇到以下JavaScript代码的问题。它有一个错误警告表示表值未定义。我正在尝试通过计算price * qty
来更新每一行的小计。
function updateSubtotal() {
var subTotal = 0;
var tables = document.getElementsByTagName("table").rows;
var r = this.parentNode.parentNode.rowIndex;
var j = document.getElementsByTagName(".price").cellIndex;
var s = document.getElementsByTagName(".subtotal").cellIndex;
var price = tables[r].cells[j].value;
var quantity = document.getElementsByTagName("input").value;
var subAmount = price * quantity;
subTotal += Number(subAmount);
// set total for the row
document.getElementsByTagName('table').rows[r].cells[s].innerHTML = '$' + subTotal.toFixed(2);
}
updateTotal();
}
我尝试更新的原始代码:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
window.onload = setupCart;
function setupCart() {
var qtyInputs = document.querySelectorAll( 'input' );
for ( var i = 0; i < qtyInputs.length; i++ ) {
qtyInputs[ i ].oninput = updateSubtotal;
}
updateTotal();
}
function updateTotal() {
var total = 0;
var subTotals = document.querySelectorAll( '.subtotal' );
for ( var i = 0; i < subTotals.length; i++ ) {
var amount = subTotals[ i ].innerHTML.match( /[0-9]+.[0-9]+/ );
total += Number( amount );
}
document.querySelector( '#total' ).innerHTML = '$' + total.toFixed( 2 );
}
</script>
</head>
<body>
><table>
><tr>
><th>Description</th>
><th>Each</th>
><th>Qty</th>
><th>subtotal</th>
></tr>
<tr class="item">
<td class="description"><a href=""><img src="red-shirt.jpg" alt="" />Red Crew Neck T-Shirt</a></td>
<td class="price">$15.00</td>
<td><input type="number" value="1" min="0" /></td>
<td class="subtotal">$15.00</td>
</tr>
<tr class="item">
<td class="description"><a href=""><img src="tropical-shirt.jpg" alt="" />Blue Tropical Floral Print T-Shirt</a></td>
<td class="price">$25.00</td>
<td><input type="number" value="1" min="0" /></td>
<td class="subtotal">$25.00</td>
</tr>
<tr class="item">
<td class="description"><a href=""><img src="black-sneakers.jpg" alt="" />Black Canvas Lace Up Sneakers</a></td>
<td class="price">$35.00</td>
<td><input type="number" value="1" min="0" /></td>
<td class="subtotal">$35.00</td>
</tr>
<tr class="item">
<td class="description"><a href=""><img src="black-grey-jacket.jpg" alt="" />Black and Grey Hooded Jacket</a></td>
<td class="price">$40.00</td>
<td><input type="number" value="1" min="0" /></td>
<td class="subtotal">$40.00</td>
</tr>
<tr class="item">
<td class="description"><a href=""><img src="black-sunglasses.jpg" alt="" />Black Retro Sunglasses</a></td>
<td class="price">$15.00</td>
<td><input type="number" value="1" min="0" /></td>
<td class="subtotal">$15.00</td>
</tr>
<tr class="cart-summary">
<td></td>
<td></td>
<th>Total:</th>
<td id="total"></td>
</tr>
</table>
</body>
</html>
答案 0 :(得分:0)
.getElementsByTagName()
函数返回一个NodeList对象。如果您想要页面上的第一个<table>
,则可以使用
document.getElementsByTagName("table")[0].rows ...
最好在函数开始时只获取一次:
var table = document.getElementsByTagName("table")[0];
避免重新遍历DOM。
答案 1 :(得分:0)
也许是因为document.getElementsByTagName不返回元素而是返回元素列表...您必须访问所需的节点,如此document.getElementsByTagName(“table”)[0] .rows