我正在使用TraitsUI中的FileDialog类,它运行得很好,除了我的生活,我还无法弄清楚如何传递默认目录,以便对话使用。
理想情况下,对话框会在本地文件系统中除树顶之外的某个位置打开...
非常感谢新手的任何见解或指导。
基本代码非常通用/标准如下。
demo_id = 'traitsui.demo.standard_editors.file_dialog.file_info'
class FileDialog ( HasTraits ):
# The name of the selected file:
file_name = File
# The button used to display the file dialog:
open = Button( 'Open...' )
#-- Traits View Definitions ------------------------------------------------
view = View(
HGroup(
Item( 'open', show_label = False ),
'_',
Item( 'file_name', style = 'readonly', springy = True )
),
width = 0.5
)
#-- Traits Event Handlers --------------------------------------------------
def _open_changed ( self ):
""" Handles the user clicking the 'Open...' button.
"""
file_name = open_file( extensions = FileInfo(), id = demo_id )
if file_name != '':
self.file_name = file_name
答案 0 :(得分:1)
我建议不使用TraitsUI FileDialog。我认为你可以使用pyface.api.FileDialog做得更好(特定于工具包;对于API,请参阅https://github.com/enthought/pyface/blob/master/pyface/i_file_dialog.py)。
答案 1 :(得分:0)
这很简单。基本上,当您执行open_file
方法时,您有机会向其传递特征定义,这些特征将依次传递给在该便捷方法中创建的OpenFileDialog
对象。您已经使用以下
open_file(extensions = FileInfo(),id = demo_id)
只需添加" file_name"的定义即可。而且你已经确定了。
open_file(file_name =" / foo / bar" extensions = FileInfo(),id = demo_id)
从traitui.file_dialog.py
的源代码中读取,您可以看到file_name从open_file
传递到OpenFileDialog
的机制,Handler负责表示文件对话框本身。
def open_file ( **traits ):
...
fd = OpenFileDialog( **traits )
...
class OpenFileDialog ( Handler ):
...
# The starting and current file path:
file_name = File
...
答案 2 :(得分:0)
可能为时已晚,但这是一个例子:
#other traits imports
from pyface.api import FileDialog
class Something(HasTraits):
txt_file_name = File
openTxt = Button('Open...')
traits_view = View(
VGroup(
HGroup(
Item( 'openTxt', show_label = False ),
'_',
Item( 'txt_file_name', style = 'readonly', width = 200 ),
),
)
)
def _openTxt_fired(self):
""" Handles the user clicking the 'Open...' button.
"""
extns = ['*.txt',]#seems to handle only one extension...
wildcard='|'.join(extns)
dialog = FileDialog(title='Select text file',
action='open', wildcard=wildcard,
default_path = self.txt_file_name)
if dialog.open() == OK:
self.txt_file_name = dialog.path
self.openTxtFile(dialog.path)
def openTxtFile(self, path):
'do something'
print path