Question

我有6个UIViewControllers与推送segue连接，带有标识符和我的应用程序中的功能，使用此方法“跳转”到所需的UIViewController以堆叠ViewControllers：

- (void) JumpTo6 {
UINavigationController *nav = self.navigationController;
UIViewController *a =[self.storyboard instantiateViewControllerWithIdentifier:@"2"];
[nav pushViewController:a animated:NO];
UIViewController *b =[self.storyboard instantiateViewControllerWithIdentifier:@"3"];
[nav pushViewController:b animated:NO];
UIViewController *c =[self.storyboard instantiateViewControllerWithIdentifier:@"4"];
[nav pushViewController:c animated:NO];
UIViewController *d =[self.storyboard instantiateViewControllerWithIdentifier:@"5"];
[nav pushViewController:d animated:NO];
UIViewController *e =[self.storyboard instantiateViewControllerWithIdentifier:@"6"];
[nav pushViewController:e animated:YES];

使用iOS7时一切正常。我会触发这个方法，假设我在UIViewController上，系统会将每个UIViewController堆叠到UI VC 6，UIViewController六个将会显示动画。

但是在iOS8上会出现奇怪的行为。系统会在短时间内向我显示UIViewcontroller 5，然后转到UIViewcontroller 6.这是我不想要的。

总结一下：

iOS 7：1 -----＆gt; 6 - 理想的

iOS 8：1 -----＆gt; 5（短暂的一段时间）----＆gt; 6 - 不受欢迎

我的问题是如何使用iOS 8实现理想效果.Ty！

Answer 1

使用方法：

- (void)setViewControllers:(NSArray *)viewControllers
              animated:(BOOL)animated

一次设置所有控制器只显示最后一个。

在你的情况下：

- (void) JumpTo6 {
  UINavigationController *nav = self.navigationController;
  UIViewController *a = [self.storyboard instantiateViewControllerWithIdentifier:@"2"];
  UIViewController *b = [self.storyboard instantiateViewControllerWithIdentifier:@"3"];
  UIViewController *c = [self.storyboard instantiateViewControllerWithIdentifier:@"4"];
  UIViewController *d = [self.storyboard instantiateViewControllerWithIdentifier:@"5"];
  UIViewController *e = [self.storyboard instantiateViewControllerWithIdentifier:@"6"];
  NSArray *viewControllers = nav.viewControllers;
  NSArray *newViewControllers = [NSArray arrayWithObjects:a, b, c, d, e, nil];
  [nav setViewControllers:[viewControllers arrayByAddingObjectsFromArray:newViewControllers] animated:YES];
}

尝试在NavigationController中推送多个UIViewControllers时出现iOS8问题

1 个答案: