Question

我有一张问卷回复表。我希望能够将我目前拥有的2个查询放在一个查询中。我已经尝试这样做了几天，并且已经搜索了很多这个网站。

这是我到目前为止所做的：

select
responses.gname,
responses.client_id,
responses.pri_cou_last,
responses.olm_team,
responses.work,
responses.resDate,
(SELECT round (avg(responses.response),2) FROM responses WHERE responses.formID='2'     AND responses.resDate<=curdate() AND responses.resDate>=DATE_SUB(NOW(), INTERVAL 30 DAY) AND responses.response>'0')
 AS avg30,
    (SELECT round(avg(responses.response),2) FROM responses WHERE responses.formID='2' AND responses.resDate<=curdate() AND responses.resDate>=DATE_SUB(NOW(), INTERVAL 7 DAY) AND    responses.response>'0')
 AS avg7
from responses
    GROUP BY responses.gname,responses.client_id
    ORDER BY responses.pri_cou_last;

这两个子查询没有做我想要的，很可能是因为他们错了。它们给出了我在7天和30天间隔内所有回复的总平均值。

以下是适用于我的7天查询的代码：

SELECT
responses.gname,
responses.olm_team,
responses.work,
round(avgresponses.response),2),
responses.pri_cou_last,
responses.client_id,
visits.client_id,
visits.bed,
visits.depdate_ymd
FROM
responses
LEFT JOIN
visits ON responses.client_id=visits.client_id
WHERE
responses.formID='2'
AND responses.resDate<=curdate() 
 AND responses.resDate>=DATE_SUB(NOW(), INTERVAL 7 DAY) 
 AND responses.response>'0' 
 AND visits.bed>'0' 
 AND visits.depdate_ymd='0000-00-00'
 GROUP BY
 responses.gname,
 responses.client_id
 ORDER BY
 responses.pri_cou_last

提前谢谢！

感谢到目前为止的回复。

是的，有一个formID列，拼写相同。

以下是我现在的代码：

 SELECT
   r1.gname,
   r1.client_id,
   r1.pri_cou_last,
   r1.olm_team,
   r1.work,
   r1.resDate,
   round(AVG(CASE WHEN formID = '2' AND response > '0' AND resDate BETWEEN DATE_SUB(NOW(), INTERVAL 7 DAY) AND CURDATE() THEN response end),2) as a7,
   round(AVG(CASE WHEN formID = '2' AND response > '0' AND resDate BETWEEN DATE_SUB(NOW(), INTERVAL 30 DAY) AND CURDATE() THEN response end),2) as a3,  
   visits.client_id,
   visits.bed,
   visits.depdate_ymd
    FROM
      responses as r1
 LEFT JOIN visits on r1.client_id=visits.client_id
    WHERE visits.bed>'0' 
     GROUP BY r1.client_id,r1.pri_cou_last
     ORDER BY r1.pri_cou_last;

问题是数据不是我想要的。在某些行上为a3和a7返回了NULL值。并且，行数不正确。

在使用客户端查看上述查询返回的数据后，我们发现此查询中的数据是正确的。它提供的数据多于原始查询，并且客户端将数据输入程序会导致此查询产生一些意外响应。但他们是正确的......

我检查了下面的1个答案，因为使用CASE确实解决了问题。我永远无法让相关的查询起作用。

再次感谢。

Answer 1

您需要使用相关子查询：

SELECT
    r1.gname,
    r1.client_id,
    r1.pri_cou_last,
    r1.olm_team,
    r1.work,
    r1.resDate,
    (SELECT round (avg(r2.response),2) 
        FROM responses AS r2
        WHERE r2.formID='2'     
            AND r2.resDate<=curdate() 
            AND r2.resDate>=DATE_SUB(NOW(), INTERVAL 30 DAY) 
            AND r2.response>'0'
            AND r2.gname = r1.gname AND r2.client_id = r1.client_id)
     AS avg30,
     (SELECT round(avg(r3.response),2)
        FROM responses AS r3
        WHERE r3.formID='2'
            AND r3.resDate<=curdate()
            AND r3.resDate>=DATE_SUB(NOW(), INTERVAL 7 DAY)
            AND r3.response>'0'
            AND r3.gname = r1.gname AND r3.client_id = r1.client_id)
     AS avg7
FROM responses AS r1
GROUP BY r1.gname,r1.client_id
ORDER BY r1.pri_cou_last;

您也可以在没有子查询的情况下执行此操作：

SELECT
    r1.gname,
    r1.client_id,
    r1.pri_cou_last,
    r1.olm_team,
    r1.work,
    r1.resDate,
    ROUND(AVG(CASE WHEN formID = '2' 
                    AND response > 0 
                    AND resDate BETWEEN DATE_SUB(NOW(), INTERVAL 30 DAY) AND CURDATE()
                   THEN response
              END) 2) AS avg30,
    ROUND(AVG(CASE WHEN formID = '2' 
                    AND response > 0 
                    AND resDate BETWEEN DATE_SUB(NOW(), INTERVAL 7 DAY) AND CURDATE()
                   THEN response
              END) 2) AS avg7
FROM responses AS r1
GROUP BY r1.gname,r1.client_id
ORDER BY r1.pri_cou_last;

Mysql子查询平均为7天和30天

1 个答案: