Question

我有以下格式的数据：

Date        Value
08/28        100
09/01        1
09/01        5
09/10        2

我希望我的输出为：

Date        Value
08/28        100
08/29        100
08/30        100
08/31        100
09/01        106
09/02        106
.
.
.
09/10        108

我刚开始使用SQL，所以任何帮助都会受到赞赏。我现在所拥有的是下面的内容，但这与我所寻求的并不相近：

SELECT  Date, COUNT(DISTINCT(Service)) AS Value
      FROM [Directory]
      WHERE Date <= @myDate
      GROUP BY Date ORDER BY Date

Answer 1

首先，您可以使用子查询来获取聚合值

SELECT  Date, (SELECT SUM(Value) FROM Directory d WHERE d.Date <= Directory.Date)
FROM [Directory]
WHERE Date <= @myDate
ORDER BY Date

这会给你一些看起来像这样的东西：

Date        Value
08/28        100
09/01        101
09/01        106
09/10        108

然后你可以添加一个Date表作为sgeddes建议。本文解释得非常好：http://michaelmorley.name/how-to/create-date-dimension-table-in-sql-server

然后您可以像这样修改您的查询

SELECT DateTable.Date, (SELECT SUM(Value) FROM Directory d WHERE d.Date <= Directory.Date)
FROM [Directory] LEFT OUTER JOIN DateTable on Directory.Date = DateTable.Date
WHERE DateTable.Date <= @myDate
ORDER BY DateTable.Date

获取您正在寻找的数据格式。

Answer 2

基于sgeddes建议：

选择a.Date，COUNT（DISTINCT（d.Service））AS值

  FROM [Directory] d
  LEFT OUTER JOIN [Date Table] a on d.Date  = a.Date 
  WHERE Date <= @myDate
  GROUP BY Date 
  ORDER BY Date

Answer 3

在sqlserver中使用以下脚本：

BEGIN
--If exist then drop temp tables
DROP TABLE #YOURTABLE;
DROP TABLE #TEST1;

DECLARE @MINDATE DATETIME;
DECLARE @MAXDATE DATETIME;

CREATE TABLE #YOURTABLE(
CDATE DATE,
VALUE INT
);
INSERT INTO #YOURTABLE VALUES ('08/28/2014',100),('09/01/2014',1),('09/01/2014',5),('09/10/2014',100);

--select start date and end date from your table
SELECT @MINDATE=MIN(CDATE),@MAXDATE=MAX(CDATE) FROM #YOURTABLE;

CREATE TABLE #TEST1(
CDATE DATE,
VALUE INT
);

;WITH CALENDAR
AS (
    SELECT @MINDATE CDATE   
    UNION ALL   
    SELECT CDATE + 1
    FROM CALENDAR
    WHERE CDATE + 1 <= @MAXDATE
    )

-- insert all dates with 0 value in temp table
INSERT INTO #TEST1 SELECT CDATE,0 FROM CALENDAR;

--delete dates which are already there in your table
DELETE FROM #TEST1 WHERE CDATE IN (SELECT CDATE FROM #YOURTABLE)

-- insert all dates with values from your table to temporary table which holds dates which are not in your table
INSERT INTO #TEST1 SELECT * FROM #YOURTABLE;

  SELECT T1.CDATE,(SELECT SUM(VALUE) FROM #TEST1 T2 WHERE T2.CDATE<=T1.CDATE) FROM #TEST1 T1
END

查询以汇总日期之间的总计

3 个答案: