假设:
#include "gmock/gmock.h"
#include <string>
using namespace testing; // tsk, tsk
// -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- --
struct Mockable {
virtual std::string ify(int x) const;
};
std::string Mockable::ify(int x) const
{
return std::to_string(x);
}
// -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- --
struct Mocked : public Mockable {
MOCK_CONST_METHOD1(ify, std::string(int));
};
// -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- --
std::string tested(Mockable const& u, int x)
{
return u.ify(x);
}
TEST(TC,T42)
{
Mocked mock;
ON_CALL(mock, ify(Eq(42)))
.WillByDefault(Return("33"));
std::string const& ret = tested(mock, 42);
EXPECT_EQ("42", ret);
}
TEST(TC,T33)
{
Mocked mock;
ON_CALL(mock, ify(Eq(33)))
.WillByDefault(Return("333"));
std::string const& ret = tested(mock, 42);
EXPECT_EQ("42", ret);
}
int main(int argc, char *argv[])
{
::testing::InitGoogleTest(&argc, argv);
//::testing::FLAGS_gmock_verbose = "info";
return RUN_ALL_TESTS();
}
输出结果为:
$ ./mocktest
[==========] Running 2 tests from 1 test case.
[----------] Global test environment set-up.
[----------] 2 tests from TC
[ RUN ] TC.T42
GMOCK WARNING:
Uninteresting mock function call - taking default action specified at:
mocktest.cc:40:
Function call: ify(42)
Returns: "33"
Stack trace:
mocktest.cc:44: Failure
Value of: ret
Actual: "33"
Expected: "42"
[ FAILED ] TC.T42 (0 ms)
[ RUN ] TC.T33
GMOCK WARNING:
Uninteresting mock function call - returning default value.
Function call: ify(42)
Returns: ""
Stack trace:
mocktest.cc:54: Failure
Value of: ret
Actual: ""
Expected: "42"
[ FAILED ] TC.T33 (1 ms)
[----------] 2 tests from TC (1 ms total)
[----------] Global test environment tear-down
[==========] 2 tests from 1 test case ran. (1 ms total)
[ PASSED ] 0 tests.
[ FAILED ] 2 tests, listed below:
[ FAILED ] TC.T42
[ FAILED ] TC.T33
在这两种情况下,Gmock的行为正确w.r.t.应用行为(或不在TC33中)。但为什么它会说&#34;无趣的模拟函数调用&#34;在这两种情况下?只有在使用EXPECT_CALL
?
答案 0 :(得分:18)
“模拟函数调用仅在使用EXPECT_CALL指定时才有意义吗?”
简而言之,是的
ON_CALL()
宏仅影响对模拟方法调用采取的操作,但不影响对模拟对象设置的调用期望。
您可以使用NiceMock<>
模板来抑制这些警告
To cite from google mocks "Cookbook"
假设您的测试使用模拟类MockFoo:
TEST(...) {
MockFoo mock_foo;
EXPECT_CALL(mock_foo, DoThis());
... code that uses mock_foo ...
}
如果调用除DoThis()之外的mock_foo方法,Google Mock会将其报告为警告。但是,如果您重写测试以改为使用NiceMock,则警告将消失,从而产生更清晰的测试输出:
using ::testing::NiceMock;
TEST(...) {
NiceMock<MockFoo> mock_foo;
EXPECT_CALL(mock_foo, DoThis());
... code that uses mock_foo ...
}
NiceMock<MockFoo>
是MockFoo
的子类,因此可以在接受MockFoo
的任何地方使用它。