Question

我有一张桌子

name       test       count 
----------------------------   
sam        test1        10
sam        test2         2
sam        passcount     5
riz        test4         3
riz        test5         4
riz        passxount     6

我想显示结果

name             test              pass count            fail count                  total count 
-------------------------------------------------------------------   
sam              test1                 7                    10                               17
sam              test2                15                     2                               17 
riz              test 4               10                     3
riz              test 5                9                     4                                  13

Answer 1

好的，花了一点时间才意识到列标题有点误导

/**
    pass = total for name minus that for current test
    fail = total count for that test in src table
    total = total count for that name
*/

select 
    t1.name,
    t1.test,
    t2.total-t1.count as pass_count,
    t1.count as fail_count,
    t2.total as total_count
from Kamrams_table as t1
inner join 
    (
    select 
        k1.name,
        sum(k1.count) as total
    from Kamrams_table as k1
    group by k1.name
    ) as t2
on t1.name = t2.name
;

注意：我相信输出表中test4和test 5之间的额外空间是一个错字？还有其他一些有用的结构：CTE和窗口函数。

在sql中将一列拆分为三列

1 个答案: