Question

while RUN2:
    chose = int(input('Type the option number from 1 to 6:'))

    if chose == 1:
        print(grossPayMsg())
        print("Your gross pay is", grosspay(workhour, hourlywage))       

    elif chose == 2:    
        print(withHoldingsMsg())
        print("Your withholdings is", withhd(workhour, hourlywage))     

    elif chose == 3:   
        print(federalTaxMsg())
        print("Your Federal Tax is", fedtax(workhour, hourlywage)) 

    elif chose == 4:    
        print(marylandTaxMsg())
        print("Your Federal Tax is", mdtax(workhour, hourlywage))

    elif chose == 5:    
        print(netPayMsg())
        print("Your Federal Tax is", net(workhour, hourlywage))

    elif chose == 6:
        print ("Thank you for using. Goodbye!")
        RUN2 = False

    else:
        print("/////// Invalid option number ///////")

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问即可。如果输入不输入选项号，我怎么能避免像下面的ValueErrors？我知道有些用户可以故意或偶然命中输入..是否有任何声明可以避免这种情况？我只学习了int（输入）或输入......

ValueError：无法将字符串转换为float

ValueError：基数为10的int（）的文字无效：＆＃39;＆＃39;

=====================================

提前非常感谢....

Answer 1

您可以通过更改此代码

删除none

if chose == 1:
        print(grossPayMsg())
        print("Your gross pay is", grosspay(workhour, hourlywage))

到

if chose == 1:
            grossPayMsg() # print is removed because when you use print it prints the return value of grossPayMsg()
            print("Your gross pay is", grosspay(workhour, hourlywage))

您可以使用strng.isnumeric()函数检查输入的字符串是否为数字。之后转换为float并将其存储在workhour和hourlywage

中

strng = input("What's your hours worked?:")
if strng.isnumeric() :
  workhour = float(strng)

为什么我的python代码抛出ValueErrors异常？

1 个答案: