我有一个显示Google日历数据的应用,但需要初次登录。我知道可以使用OAuth 2.0存储令牌,但我不知道如何去做。这是我的代码如下。我希望网页能够使用谷歌日历中的JSON数据显示日历而无需登录。
控制器
angular.module('demo', ["googleApi"])
.config(function(googleLoginProvider) {
googleLoginProvider.configure({
clientId: '239511214798.apps.googleusercontent.com',
scopes: ["https://www.googleapis.com/auth/userinfo.email", "https://www.googleapis.com/auth/calendar", "https://www.googleapis.com/auth/plus.login"]
});
})
.controller('DemoCtrl', ['$scope', 'googleLogin', 'googleCalendar', 'googlePlus', function ($scope, googleLogin, googleCalendar, googlePlus) {
$scope.login = function () {
googleLogin.login();
};
$scope.$on("googlePlus:loaded", function() {
googlePlus.getCurrentUser().then(function(user) {
$scope.currentUser = user;
});
})
$scope.currentUser = googleLogin.currentUser;
$scope.loadEvents = function() {
this.calendarItems = googleCalendar.listEvents({calendarId: this.selectedCalendar.id});
}
$scope.loadCalendars = function() {
$scope.calendars = googleCalendar.listCalendars();
}
}]);
googleAPi
angular.module('googleApi', [])
.value('version', '0.1')
.service("googleApiBuilder", function($q) {
this.loadClientCallbacks = [];
this.build = function(requestBuilder, responseTransformer) {
return function(args) {
var deferred = $q.defer();
var response;
request = requestBuilder(args);
request.execute(function(resp, raw) {
if(resp.error) {
deferred.reject(resp.error);
} else {
response = responseTransformer ? responseTransformer(resp) : resp;
deferred.resolve(response);
}
});
return deferred.promise;
}
};
this.afterClientLoaded = function(callback) {
this.loadClientCallbacks.push(callback);
};
this.runClientLoadedCallbacks = function() {
for(var i=0; i < this.loadClientCallbacks.length; i++) {
this.loadClientCallbacks[i]();
}
};
})
.provider('googleLogin', function() {
this.configure = function(conf) {
this.config = conf;
};
this.$get = function ($q, googleApiBuilder, $rootScope) {
var config = this.config;
var deferred = $q.defer();
return {
login: function () {
gapi.auth.authorize({ client_id: config.clientId, scope: config.scopes, immediate: false}, this.handleAuthResult);
return deferred.promise;
},
handleClientLoad: function () {
gapi.auth.init(function () { });
window.setTimeout(checkAuth, 1);
},
checkAuth: function() {
gapi.auth.authorize({ client_id: config.clientId, scope: config.scopes, immediate: true }, this.handleAuthResult );
},
handleAuthResult: function(authResult) {
if (authResult && !authResult.error) {
var data = {};
$rootScope.$broadcast("google:authenticated", authResult);
googleApiBuilder.runClientLoadedCallbacks();
deferred.resolve(data);
} else {
deferred.reject(authResult.error);
}
},
}
};
})
.service("googleCalendar", function(googleApiBuilder, $rootScope) {
var self = this;
var itemExtractor = function(resp) { return resp.items; };
googleApiBuilder.afterClientLoaded(function() {
gapi.client.load('calendar', 'v3', function() {
self.listEvents = googleApiBuilder.build(gapi.client.calendar.events.list, itemExtractor);
self.listCalendars = googleApiBuilder.build(gapi.client.calendar.calendarList.list, itemExtractor);
self.createEvent = googleApiBuilder.build(gapi.client.calendar.events.insert);
$rootScope.$broadcast("googleCalendar:loaded")
});
});
})
.service("googlePlus", function(googleApiBuilder, $rootScope) {
var self = this;
var itemExtractor = function(resp) { return resp.items; };
googleApiBuilder.afterClientLoaded(function() {
gapi.client.load('plus', 'v1', function() {
self.getPeople = googleApiBuilder.build(gapi.client.plus.people.get);
self.getCurrentUser = function() {
return self.getPeople({userId: "me"});
}
$rootScope.$broadcast("googlePlus:loaded")
});
});
})
答案 0 :(得分:0)
您要做的是在结果返回后,您需要将其保存到localStorage或cookie,然后在将来使用它(如果存在)。
基本上,您需要更新handleAuthResult以存储Google API的结果:
handleAuthResult: function (authResult) {
if (authResult && !authResult.error) {
var data = {};
$rootScope.$broadcast("google:authenticated", authResult);
googleApiBuilder.runClientLoadedCallbacks();
// here you will store the auth_token
window.localStorage.setItem('auth_token', authResult.token /*I don't know what this response looks like, but it should be similar to this*/ );
deferred.resolve(data);
} else {
deferred.reject(authResult.error);
}
},