Question

我从Jenkins的文件中运行脚本。命令：

psexec -i -s cmd.exe /c echo . | powershell.exe -file "c:\Program Files (x86)\Applications\Jenkins\jobs\Deploy\workspace\Deploy\script.ps1"

如何传递“build”变量的值？

请帮帮我感谢

Answer 1

您只需按照您的参数跟踪路径即可。如：

psexec -i -s cmd.exe /c echo . | powershell.exe -file "c:\Program Files (x86)\Applications\Jenkins\jobs\Deploy\workspace\Deploy\script.ps1" '-build 1.0'

您可以看到PowerShell.exe here的命令行语法。它显示：

PowerShell[.exe]
       [-File <FilePath> [<Args>]]

如果这对您不起作用，您可以尝试在脚本块中点源脚本，例如：

psexec -i -s cmd.exe /c echo . | powershell.exe -command {. "c:\Program Files (x86)\Applications\Jenkins\jobs\Deploy\workspace\Deploy\script.ps1" -build 1}

Answer 2

我在剧本中犯了错误。我忘了插入以下代码：

Param(
  [int32]$build=0
)

As TheMadTechnician said，运行脚本的命令是：

psexec -i -s cmd.exe /c echo . | powershell.exe -file "c:\Program Files (x86)\Applications\Jenkins\jobs\Deploy\workspace\Deploy\script.ps1" -build %BUILD_NUMBER%

PowerShell：传递参数

2 个答案: