Question

我想找到连续的匹配硬币面。我设法使它连续3个匹配的尾部将结束循环。

但是我怎么能包括头（它似乎忽略了头）？

例如：

0 is heads 
reset 
0 is heads 
reset 
1 is tails 
1 is tails 
1 is tails 
total flips took is: 5

PHP：

$flipCounts = 0;
$matchingFaceTypes = 0;

$targetReached = false;
while ($matchingFaceTypes < 3 ) { 
    $faceType = rand(0, 1); 
    $flipCounts++; 
    if($faceType == 0) { 
        $matchingFaceTypes++;
        echo $faceType . " is heads ". "\n";
        }
    if($faceType == 1) {

        $matchingFaceTypes++;
        echo $faceType." is tails ". "\n";

    } else {
            $matchingFaceTypes =0;
            echo " reset ". "\n";
        }
    } echo "total flips took is: " . $flipCounts;

Answer 1

$maxMatches = 3;
$matches = array('tails' => 0, 'heads' => 0, 'total' => 0);

while(max($matches['tails'], $matches['heads']) < $maxMatches) { 
    $faceType = rand(0, 1); 
    if ($faceType) { 
       $matches['heads']++;
       $matches['tails'] = 0;
       echo $faceType . " is heads\n";
    }
    else {
       $matches['tails']++;
       $matches['heads'] = 0;
       echo $faceType . " is tails\n";
    }
    $matches['total']++;
}

echo "total flips took is: " . $matches['total'];

说到max（）

$maxMatches = 3;
$total = 0;
$matches = array('tails' => 0, 'heads' => 0);

while(max($matches) < $maxMatches) { 
    $faceType = rand(0, 1); 
    if ($faceType) { 
       $matches['heads']++;
       $matches['tails'] = 0;
       echo $faceType . " is heads\n";
    }
    else {
       $matches['tails']++;
       $matches['heads'] = 0;
       echo $faceType . " is tails\n";
    }
    $total++;
}

echo "total flips took is: " . $total;

Answer 2

else指的是第二个if，所以如果$ facetype == 0

则会采用else

下一个问题：您没有检查最后一个类型是否与之前的类型相同

我建议使用一个名为$lasttype的变量并检查$faceType是否等于该变量，如果没有重置计数器，则在此之后执行输出

$flipCounts = 0;
$matchingFaceTypes = 0;
$ctype=0;
$targetReached = false;
$lasttype=-1;

while ($matchingFaceTypes < 3 ) { 
    $faceType = rand(0, 1); 
    $flipCounts++; 
    if($faceType != $lasttype) {
        if($lasttype!=-1)
            echo " reset ". "\n<br/>";
        $lasttype=$faceType;
        $matchingFaceTypes =0;
    }

    if($faceType == 0) { 
        $matchingFaceTypes++;
        echo $faceType . " is heads ". "\n<br/>";
    }else{
        $matchingFaceTypes++;
        echo $faceType." is tails ". "\n<br/>";
    }    
} 
echo "total flips took is: " . $flipCounts;

如何连续找到匹配的硬币？

2 个答案: