Question

def changeList(myList):
    myList = myList[3:]
    new_list = []

    count = -1
    for line in myList:
        count += 1
        new_list += [list(myList[count])]

    count1 = -1
    for i in new_list:

         count1 += 1
         count2 = -1

         for j in i:

             count2 += 1

             if j == "-":
                 new_list[count1][count2] = 0 #- 0 - Can't go there.
             elif j == "|":
                 new_list[count1][count2] = 0 #| 0 - Can't go there.
             elif j == "+":
                 new_list[count1][count2] = 0 #+ 0 - Can't go there.
             elif j == " ":
                 new_list[count1][count2] = 1 #Blank - 1 for empty cell.

    for i in new_list:

       print(i)

    return new_list

为什么我这样做......

print(type(new_list[0][0]))

它将类型返回为字符串？我需要它像我分配它一样的int。当我打印出new_list时。它没有显示内容为[＆＃34; 0＆＃34;，＆＃34; 0＆＃34;，....等]它将它们显示为[0,0,0 ......等]他们必须是整数。我在这里想念的是什么感谢。

进入函数（myList）的参数I看起来像这样......

['10 20', '1 1', '10 20', '-----------------------------------------', '|     |       | | |       |     | |     |', '|-+ +-+-+ + + + + + +-+ + + +-+-+ + + +-|'...etc

我想去

new_list[0][0] = 3

但它不会让我！？

Answer 1

myList，你的输入有字符串值。

myList = ['|     |       | | |       |     | |     |', '|-+ +-+-+ + + + + + +-+ + + +-+-+ + + +-|']

您将列表转换为2d列表。

new_list = [list(i) for i in myList]

现在我们将字符串值循环更改为整数。

count1 = -1
for i in new_list:
    count1 += 1
    count2 = -1

    for j in i:

        count2 += 1
        if j == "-":
            new_list[count1][count2] = 0 #- 0 - Can't go there.
        elif j == "|":
            new_list[count1][count2] = 0 #| 0 - Can't go there.
        elif j == "+":
            new_list[count1][count2] = 0 #+ 0 - Can't go there.
        elif j == " ":
            new_list[count1][count2] = 1 #Blank - 1 for empty cell.
         # else: # Currently you don't have an else, so that makes me guess that you are getting a value you are not expecting.
         else:
             print("ERROR: THERE IS AN ISSUE HERE")
             new_list[count1][count2] = -1

我不知道您可能拥有二进制数据的确切输入。如果是这种情况，那么你必须相应地编码/解码。

我没有遇到你的问题。

print(type(new_list[0][0]))
<class "int">

因此您获得了意外的输入值。

您可以尝试强制使用int。

int(new_list[0][0])

如果您需要有关正在打印的内容的更多信息，请使用repr方法。

print(repr(new_list[0][0]))

像Jeff Langemeier建议的那样列举。

for i, li in enumerate(new_list):
    for j, item in enumerate(li):
        if item == "-":
            li[j] = 0 #- 0 - Can't go there.
        elif item == "|":
            li[j] = 0 #| 0 - Can't go there.
        elif item == "+":
            li[j] = 0 #+ 0 - Can't go there.
        elif item == " ":
            li[j] = 1 #Blank - 1 for empty cell.
        else:
            print("ERROR")
            li[j] = -1

初学者。 Python列表。英特尔＆amp;字符串

1 个答案: