ios 8应用程序中的错误 - 搜索栏正在搜索但未在屏幕上显示数据

Question

我正试图在xcode上创建一个ios应用程序 - http://www.appcoda.com/search-bar-tutorial-ios7/。当我输入搜索栏时，一切都在控制台中工作，但输出没有显示在屏幕上

@interface AllUseraStatusViewController ()
@property (weak, nonatomic) IBOutlet UITableView *statusText;
@property (weak, nonatomic) IBOutlet UITableView *statusTime;
@property (weak, nonatomic) IBOutlet UITableView *statusUserName;
@property (strong,nonatomic) NSArray *statusList;
@property (strong,nonatomic) NSMutableArray *allStatusLists;
@property(strong,nonatomic) NSArray *searchResults;
@property(strong,nonatomic) PFObject *object;
@end

@implementation AllUseraStatusViewController

- (void)viewDidLoad {
    [super viewDidLoad];
    PFQuery *query = [PFQuery queryWithClassName:@"Status"];
    [query includeKey:@"user"];
    [query orderByDescending:@"createdAt"];

    [query findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) {
        // 3
        if (!error){
            self.statusList = objects;
            [self.tableView reloadData];
        } else {
            // 4
            [[[UIAlertView alloc] initWithTitle:@"Error" message:[error userInfo][@"error"] delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil] show];
        }
    }];


}
- (CGFloat)tableView:(UITableView *)tableView heightForRowAtIndexPath:(NSIndexPath *)indexPath
{
    return 70;
}

-(NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section
{
    if(tableView==self.searchDisplayController.searchResultsTableView)
    {
        return [self.searchResults count];
    }else{
        return [self.statusList count];
    }

}
-(UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
    static NSString *simpleTableIdentifier= @"AllUsersStatusCell";
    UITableViewCell *cell =[tableView dequeueReusableCellWithIdentifier:simpleTableIdentifier];
    if (cell==nil){
        cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:simpleTableIdentifier];

    }
    if (tableView == self.searchDisplayController.searchResultsTableView){
        self.object =[self.searchResults objectAtIndex:indexPath.item];
        NSLog(@"THIS IS object %@",self.object); 
    }else{
        self.object =[self.statusList objectAtIndex:indexPath.item];
    }
    NSLog(@"THIS IS objectttt %@",self.object); <--this prints correct status in console
    UILabel *statusText = (UILabel *)[cell viewWithTag:100];
    [statusText setText:[self.object objectForKey:@"status"]];
    NSLog(@"THIS IS objectttt %@",statusText);<--but this prints null in console

    UILabel *statusTime = (UILabel *)[cell viewWithTag:101];
    [statusTime setText:[[self.object createdAt] description]];

    UILabel *statusUserName = (UILabel *)[cell viewWithTag:102];
    PFUser *userName = [self.object objectForKey:@"user"];
    [statusUserName setText:userName.username];

    return cell;
}


- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender {
    if ([segue.identifier isEqualToString:@"detail"]) {
        NSIndexPath *indexPath = [self.tableView indexPathForSelectedRow];
        UserProfileViewController *vc = segue.destinationViewController;
        PFObject *object = [self.statusList objectAtIndex:indexPath.row];
        vc.statusObject=object;
    }
}
-(BOOL)searchDisplayController:(UISearchDisplayController *)controller      shouldReloadTableForSearchString:(NSString *)searchString
{
    [self filterContentForTextSearch:searchString
                               scope:[[self.searchDisplayController.searchBar scopeButtonTitles]
                                      objectAtIndex:[self.searchDisplayController.searchBar selectedScopeButtonIndex]]];
    return YES;
}

-(void)filterContentForTextSearch:(NSString *)searchText scope:(NSString *)scope
{
    NSPredicate *resultPredicate=[NSPredicate predicateWithFormat:@"status contains[c] %@",searchText];
    NSLog(@"THIS IS %@",resultPredicate);
    self.searchResults = [self.statusList filteredArrayUsingPredicate:resultPredicate];
    NSLog(@"THIS IS THE %@", self.searchResults);
}

@end

让错误更清晰

这是上面代码中的错误

 NSLog(@"THIS IS object %@",self.object);// this prints correct object 
 UILabel *statusText = (UILabel *)[cell viewWithTag:100]; 
 [statusText setText:[self.object objectForKey:@"status"]]; 
 NSLog(@".....THIS IS objectt %@",statusText.text);// it prints null on console 
 NSLog(@".....THIS IS objectttt %@",[self.object objectForKey:@"status"]);// this prints correct o/p