我得到了这段代码并且它已经老了，我知道我需要将它转换为PDO（仍然在学习），但我现在需要让它正常工作。
我正在尝试根据查询发送多封电子邮件。所以在这个特定的查询中，我得到两个结果。所以我需要向该组发送两封不同的电子邮件。如果查询有4个结果，那么我需要发送4.现在它只发送第一个结果。如何让它循环并发送多封电子邮件。
以下是代码：
<?
// connection string ......
$production = "SELECT value1 FROM parameters WHERE name = 'IS_PRODUCTION' ";
$query = "SELECT accounts.username, email_activate.email, accounts.user_id, accounts.alt_id FROM accounts INNER JOIN email_activate ON accounts.user_id = email_activate.user_id WHERE dt_welcome = '0000-00-00 00:00:00' AND dt_start <= DATE_SUB(NOW(), INTERVAL 3 DAY)";
$result = mysql_query($query) or die(mysql_error());
while ($row = mysql_fetch_array($result)) {
$message = "Hello ".$row['username'].", <br/><br/>";
$message .= "You recently subscribed to <bblah blah blah</b> ";
$message .= '(<a href="http://">http://</a>), ' ;
$message .= "the official ";
$message .= "source of <br /><br /> ";
if ($production == 'Y' ) {
$subject = "How can we Assist!";
$to = "".$row['email']."";
$result2 = mysql_query("UPDATE email_activate SET dt_welcome = NOW() WHERE user_id = '".$row['user_id']."' ");
} else {
$subject = "[TEST] Offer You Assistance";
$to = 'email1@email.com' . ', ';
$to .= 'email2@email.com ' . ', ';
$to .= 'email3@email.com';
$result2 = mysql_query("UPDATE email_activate SET dt_welcome = NOW() WHERE user_id = '".$row['user_id']."' ");
}
$headers = "Content-Type: text/html; charset=utf-8\r\n";
$queryEmail = "SELECT alt_id FROM lookup_roles WHERE spec_tag = 'public_email'";
$result3 = mysql_query($queryEmail) or die(mysql_error());
while ($row12 = mysql_fetch_array($resul3t)) {
mail($to, $subject, $message, $headers, "-f ".$row12[alt_id]."");
}
}
?>
所以我修复了它，上面的代码工作得很好。我忘了使用不同的$ result变量---＆gt;将它从$ result更改为$ result3，这样它就不会删除之前的结果，这就是为什么我只收到1封电子邮件。我知道这很简单，只是无法看到它。