Question

我有5个班级：

1）EmployeeMainTable.cs （Employeeid是主键，员工ID是其他类的外键）

2）EmployeeFamilyTable.cs

3）previousEmployeement.cs

4）employeeaddress.cs

5）employeeEducation.cs

每个类都包含相应的属性输入代码

现在我要为每个班级做些什么我创建了5个视图来输入数据，每个视图都包含提交按钮以转到下一个视图

我的问题是，当我在上一个视图中点击完成按钮时，我想立即保存所有模型。

使用mvc 4时请理解问题

我试过以下结果：

@model SecondStep
@using(Html.BeginForm("ThirdStep", "controllerName", FormMethod.Post))
{ 
    @Html.HiddenFor(model => ViewBag.FirstStepModel.Value) 
    @Html.EditorFor(model => model.Value)
    <input type="submit" value="Next"/>
}

CS1963: An expression tree may not contain a dynamic operation

中出错

@Html.HiddenFor(model => ViewBag.FirstStepModel.Value)

Line 13: { 
Line 14:
Line 15: @Html.HiddenFor(model=>ViewBag.FirstStepModel) this line giving error 
Line 16: @Html.EditorFor(model => model.SecondStepProp) 
Line 17:

Answer 1

您应该将以前的视图模型多次传递给＆＃34; next＆＃34;查看，所以当＆＃34;完成＆＃34;单击按钮，您可以检索所有模型（在控制器中）以在最后创建。（别忘了把你的模型放在帖子中）

<强> UPDATE1：

为什么在控制器上需要GET和POST方法？

USPDATE2：示例

**案例1：如果您有多个视图模型**

<强>控制器

[HttpGet]
public ActionResult FirstStep()
{
    return View(new FirstStepModel());
}

[HttpPost]
public ActionResult SecondStep(FirstStepModel firstStepModel)
{
    ViewBag.FirstStepModel = firstStepModel;
    return View(new SecondStepModel());
}

[HttpPost]
public ActionResult ThridStep(FirstStepModel firstStepModel, SecondStepModel secondStepModel)
{
    ViewBag.FirstStepModel = firstStepModel;
    ViewBag.SecondStepModel = secondStepModel;
    return View(new ThirdStepModel());
}

[HttpPost]
public ActionResult FourthStep(FirstStepModel firstStepModel, SecondStepModel secondStepModel, ThirdStepModel thirdStepModel)
{
    ViewBag.FirstStepModel = firstStepModel;
    ViewBag.SecondStepModel = secondStepModel;
    ViewBag.ThirdStepModel = thirdStepModel;
    return View(new FourthStepModel()));
}

[HttpPost]
public ActionResult FifthStep(FirstStepModel firstStepModel, SecondStepModel secondStepModel, ThirdStepModel thirdStepModel, FourthStepModel fourthStepModel)
{
    ViewBag.FirstStepModel = firstStepModel;
    ViewBag.SecondStepModel = secondStepModel;
    ViewBag.ThirdStepModel = thirdStepModel;
    ViewBag.FourthStepModel = fourthStepModel;
    return View(new FinalStepModel());
}

[HttpPost]
public ActionRestul Finish(FirstStepModel firstStepModel, SecondStepModel secondStepModel, ThirdStepModel thirdStepModel, FourthStepModel fourthStepModel, FifthStepModel fifthStepModel)
{
    // DB Save ?
}

<强>视图 FirstStep：

@model FirstStep
@using(Html.BeginForm("SecondStep", "controllerName", FormMethod.Post))
{
    @Html.EditorFor(model => model.Value)
    <input type="submit" value="Next"/>
}

SecondStep：

@model SecondStep
@using(Html.BeginForm("ThirdStep", "controllerName", FormMethod.Post))
{ 
    @Html.HiddenFor(model => ViewBag.FirstStepModel.Value) 
    @Html.EditorFor(model => model.Value)
    <input type="submit" value="Next"/>
}

ThirdStep：

@model ThirdStep
@using(Html.BeginForm("FourthStep", "controllerName", FormMethod.Post))
{  
    @Html.HiddenFor(model => ViewBag.FirstStepModel.Value) 
    @Html.HiddenFor(model => ViewBag.SecondStepModel.Value) 
    @Html.EditorFor(model => model.Value)
    <input type="submit" value="Next"/>
}

FourthStep：

@model FourthStep
@using(Html.BeginForm("FifthStep", "controllerName", FormMethod.Post))
{
    @Html.HiddenFor(model => ViewBag.FirstStepModel.Value) 
    @Html.HiddenFor(model => ViewBag.SecondStepModel.Value) 
    @Html.HiddenFor(model => ViewBag.ThirdStepModel.Value) 
    @Html.EditorFor(model => model.Value)
    <input type="submit" value="Next"/>
}

FifthStep：

@model FifthStep
@using(Html.BeginForm("Finish", "controllerName", FormMethod.Post))
{
    @Html.HiddenFor(model => ViewBag.FirstStepModel.Value) 
    @Html.HiddenFor(model => ViewBag.SecondStepModel.Value) 
    @Html.HiddenFor(model => ViewBag.ThirdStepModel.Value) 
    @Html.HiddenFor(model => ViewBag.FifthStepModel.Value) 
    @Html.EditorFor(model => model.Value)
    <input type="submit" value="Next"/>
}

案例2：单一视图模型 小心：要实现这一点，您需要（取决于您的模型的复杂性）模型的ModelBinder

[HttpGet]
public ActionResult FirstStep()
{
    return View("FirstStep", new Model());
}

[HttpPost]
public ActionResult SecondStep(Model model)
{
    return View("SecondStep", model);
}

[HttpPost]
public ActionResult ThridStep(Model model)
{
    return View("ThirdStep", model);
}

[HttpPost]
public ActionResult Finish(Model model)
{
    // DB Save ?
}

...

<强>视图

FirstStep：

@model Model
@using(Html.BeginForm("SecondStep", "controllerName", FormMethod.Post))
{
    @Html.EditorFor(model => model.Step1Value)
    <input type="submit" value="Next"/>
}

SecondStep：

@model Model
@using(Html.BeginForm("ThirdStep", "controllerName", FormMethod.Post))
{
    @Html.HiddenFor(model => model.Step1Value)
    @Html.EditorFor(model => model.Step2Value)
    <input type="submit" value="Next"/>
}

ThirdStep：

@model Model
@using(Html.BeginForm("Finish", "controllerName", FormMethod.Post))
{
    @Html.HiddenFor(model => model.Step1Value)
    @Html.HiddenFor(model => model.Step2Value)
    @Html.EditorFor(model => model.Step3Value)
    <input type="submit" value="Next"/>
}

在mvc中一次保存多个视图模型数据

1 个答案: