我在值中包含以下代码和数字：
我想要下面的所有代码：
<option value="1" class="sub_1">
更改为：
<option value="" id="1" class="sub_1">
实际上我希望值为空，值内的数字将另一个ID放在选项中，如id =＆＃34;＆＃34;或data-id =＆＃34;＆＃34;或.... ....
http://code.jquery.com/jquery-1.11.1.min.js
function cascadeSelect(parent, child) {
var childOptions = child.find('option:not(.static)');
child.data('options', childOptions);
parent.change(function() {
childOptions.remove();
child
.append(child.data('options').filter('.sub_' + this.value))
.change();
})
childOptions.not('.static, .sub_' + parent.val()).remove();
}
$(function() {
cascadeForm = $('.cascadeTest');
orgSelect = cascadeForm.find('.orgSelect');
terrSelect = cascadeForm.find('.terrSelect');
locSelect = cascadeForm.find('.locSelect');
cascadeSelect(orgSelect, terrSelect);
cascadeSelect(terrSelect, locSelect);
});<form action="#" class="cascadeTest">
<table>
<tr>
<th>Organization:</th>
<td>
<select name="orgSelect" class="orgSelect">
<option value="0">Select an Organization</option>
<option value="1">Organization 1</option>
<option value="2">Organization 2</option>
<option value="3">Organization 3</option>
</select>
</td>
</tr>
<tr>
<th>Territory:</th>
<td>
<select name="terrSelect" class="terrSelect">
<option value="0" class="static">- All Territories -</option>
<option value="1" class="sub_1">Organization 1 - Territory 1</option>
<option value="2" class="sub_1">Organization 1 - Territory 2</option>
<option value="3" class="sub_2">Organization 2 - Territory 1</option>
<option value="4" class="sub_2">Organization 2 - Territory 2</option>
<option value="5" class="sub_3">Organization 3 - Territory 1</option>
<option value="6" class="sub_3">Organization 3 - Territory 2</option>
<option value="7" class="sub_3">Organization 3 - Territory 3</option>
</select>
</td>
</tr>
<tr>
<th>Location:</th>
<td>
<select name="locSelect" class="locSelect">
<option value="0" class="static">- All Locations -</option>
<option value="1" class="sub_1">Organization 1 - Territory 1 - Location 1</option>
<option value="1" class="sub_1">Organization 1 - Territory 1 - Location 2</option>
<option value="2" class="sub_2">Organization 1 - Territory 2 - Location 1</option>
<option value="2" class="sub_2">Organization 1 - Territory 2 - Location 2</option>
<option value="3" class="sub_3">Organization 2 - Territory 1 - Location 1</option>
<option value="3" class="sub_3">Organization 2 - Territory 1 - Location 2</option>
<option value="4" class="sub_4">Organization 2 - Territory 2 - Location 1</option>
<option value="5" class="sub_5">Organization 3 - Territory 1 - Location 1</option>
<option value="6" class="sub_6">Organization 3 - Territory 2 - Location 1</option>
<option value="7" class="sub_7">Organization 3 - Territory 3 - Location 1</option>
</select>
</td>
</tr>
</table>
</form>
答案 0 :(得分：1)
修改
在问题发生变化时编辑我的整个答案。 因为您只想让用户选择基于另一个选择当前值的选项。
首先，我已将terrSelect和locSelect设为disabled作为默认值。因此，用户必须首先选择orgSelect。 orgSelect更改后，我们会启用terrSelect。然后，我们遍历所有terrSelect子元素，并禁用那些与locSelect的值不匹配的子元素。然后对locSelect：
<form action="#" class="cascadeTest">
<table>
<tr>
<th>Organization:</th>
<td>
<select name="orgSelect" class="orgSelect">
<option value="0">Select an Organization</option>
<option value="1">Organization 1</option>
<option value="2">Organization 2</option>
<option value="3">Organization 3</option>
</select>
</td>
</tr>
<tr>
<th>Territory:</th>
<td>
<select name="terrSelect" class="terrSelect" disabled="disabled">
<option value="0" class="static">- All Territories -</option>
<option value="1" class="sub_1">Organization 1 - Territory 1</option>
<option value="2" class="sub_1">Organization 1 - Territory 2</option>
<option value="3" class="sub_2">Organization 2 - Territory 1</option>
<option value="4" class="sub_2">Organization 2 - Territory 2</option>
<option value="5" class="sub_3">Organization 3 - Territory 1</option>
<option value="6" class="sub_3">Organization 3 - Territory 2</option>
<option value="7" class="sub_3">Organization 3 - Territory 3</option>
</select>
</td>
</tr>
<tr>
<th>Location:</th>
<td>
<select name="locSelect" class="locSelect" disabled="disabled">
<option value="0" class="static">- All Locations -</option>
<option value="1" class="sub_1">Organization 1 - Territory 1 - Location 1</option>
<option value="1" class="sub_1">Organization 1 - Territory 1 - Location 2</option>
<option value="2" class="sub_2">Organization 1 - Territory 2 - Location 1</option>
<option value="2" class="sub_2">Organization 1 - Territory 2 - Location 2</option>
<option value="3" class="sub_3">Organization 2 - Territory 1 - Location 1</option>
<option value="3" class="sub_3">Organization 2 - Territory 1 - Location 2</option>
<option value="4" class="sub_4">Organization 2 - Territory 2 - Location 1</option>
<option value="5" class="sub_5">Organization 3 - Territory 1 - Location 1</option>
<option value="6" class="sub_6">Organization 3 - Territory 2 - Location 1</option>
<option value="7" class="sub_7">Organization 3 - Territory 3 - Location 1</option>
</select>
</td>
</tr>
</table>
</form>
<script>
$('.orgSelect').change(function(){
selected = $(this).val();
$('.terrSelect').removeAttr('disabled');
$('.terrSelect').children('option').each(function(){
if( !$(this).hasClass( 'sub_'+selected ) ){
$(this).attr('disabled','disabled');
}
else {
$(this).removeAttr('disabled');
}
});
});
$('.terrSelect').change(function(){
selected = $(this).val();
$('.locSelect').removeAttr('disabled');
$('.locSelect').children('option').each(function(){
if( !$(this).hasClass( 'sub_'+selected ) ){
$(this).attr('disabled','disabled');
}
else {
$(this).removeAttr('disabled');
}
});
});
</script>
答案 1 :(得分：1)
这是你朋友说我无法用其他内容填充值的事情
见我的朋友们 我想要所有的代码如下：
<option value="1" class="sub_3">hello</option>
更改为：
<option value="hello" id="1" class="sub_1">hello</option>
这些值将填充其他内容，例如hello和值内的数字填写其他id并且脚本没有问题