void write_token_to_data()
{
typedef double* DynamicMatrix[l+m];
// DynamicMatrix Count;
typedef double* DynamicMatrix2[l+m];
//DynamicMatrix2 Prob;
for(int i=0; i<(l+m); i++)
{
for(int j=0; j<(l+m); j++)
{
if(mysqlinsert2(i,j,combine[i],combine[j]))
{
cout<<"insert OK!!"<<endl;
}
else
{
cout<<"insert failed"<<endl;
}
}
}
}//end of function
这是我的问题 我怎么能改变这个子功能,我可以保持i,j结合[i],结合[j] 直到数字100,并将这四个值抛入mysqlinsert函数 并在for循环索引101中释放数组并继续记录值,长话短说,我想把这个mysql插入到小部分中
答案 0 :(得分:1)
- You can contruct a string in the form
(i,j,cobine[i],combine[j]) for each iteration.
- Inorder to insert a multiple rows in a single query.
[Normal insert query for multiple records
INSERT INTO Table ( Column1, Column2 ) VALUES
( Value1, Value2 ), ( Value1, Value2 )
]
- also rewrite mysqlinsert2(i,j,combine[i],combine[j]) into *mysqlinsert2(str)*.and execute the string.
for(int i=0; i<(l+m); i++){
for(int j=0; j<(l+m); j++){
if (till count => 100) {
// concatinate the string with prev str
str += (i,j,combine[i],combine[j])+',';
}
if (count reaches hundred || count = 0) {
// execute the string
mysqlinsert2(str);
// initialize str as empty string
str = 'INSERT INTO Table ( Column1, Column2, column3, column4 ) VALUES';
count = 0;
}
}
}