Question

我突然得到了这个错误在那之前它工作得很好，..

我的日期格式＆＃34; 2014年9月11日下午3:31＆＃34;

public boolean validateLuckyDrawExpirationDate(String strExpirationDate) throws Exception{                  


            SimpleDateFormat df=new SimpleDateFormat("MMM dd yyyy hh:mmaa");
            Date expirationDateObj=df.parse(strExpirationDate);
            Date today=new Date();

            boolean isAfter=today.after(expirationDateObj);

            boolean isBefore=today.before(expirationDateObj);

            Log.v("isToday", String.valueOf(isAfter));
            Log.v("isBefore", String.valueOf(isBefore));

            Log.v("Original date", String.valueOf(expirationDateObj));
            Log.v("SimpleDateFormat", String.valueOf(df.format(expirationDateObj)));
            Log.e("startDate...2",strExpirationDate);

            return isBefore;

    }

Answer 1

正如您的问题标题所示，您正在解析null此方法。这样unparseable date:“null”就会因此而得到。

此方法对Sep 11 2014 3:31PM

没有任何问题

Answer 2

您确定要使用参数值validateLuckyDrawExpirationDate()调用方法Sep 11 2014 3:31PM吗？

尝试将代码放入try-catch块：

public boolean validateLuckyDrawExpirationDate(String strExpirationDate) throws Exception{                  
    Boolean isBefore = false;
    try{

        SimpleDateFormat df=new SimpleDateFormat("MMM dd yyyy hh:mmaa");
        Date expirationDateObj=df.parse(strExpirationDate);
        Date today=new Date();

        boolean isAfter=today.after(expirationDateObj);

        isBefore=today.before(expirationDateObj);

        Log.v("isToday", String.valueOf(isAfter));
        Log.v("isBefore", String.valueOf(isBefore));

        Log.v("Original date", String.valueOf(expirationDateObj));
        Log.v("SimpleDateFormat", String.valueOf(df.format(expirationDateObj)));
        Log.e("startDate...2",strExpirationDate);
    } 
    catch (ParseException e) {
        Toast.makeText(getApplicationContext(), "Date is not valid!",
                       Toast.LENGTH_LONG).show();
    }
        return isBefore;

}

无法解析的日期：＆＃34; null＆＃34; （在偏移0处）android

2 个答案: