Question

我似乎无法得到这个，我只是不了解如何在模块之间传递参数。这对我来说似乎很简单，但也许我只是没有得到它，我对python很新，但确实有编程经验。

def main():

  weight = input("Enter package weight: ")

  return weight

def CalcAndDisplayShipping(weight):

  UNDER_SIX = 1.1
  TWO_TO_SIX = 2.2
  SIX_TO_TEN = 3.7
  OVER_TEN = 3.8

  shipping = 0.0

  if weight > 10:
    shipping = weight * OVER_TEN
  elif weight > 6:
    shipping = weight * SIX_TO_TEN
  elif weight > 2:
    shipping = weight * TWO_TO_SIX
  else:
    shipping = weight * UNDER_SIX

  print ("Shipping Charge: $", shipping)


main(CalcAndDisplayShipping)

当我运行时，我得到：输入包装重量：（num）TypeError：不可拆卸的类型：function（）＆gt; INT（）

有人能解释一下吗？

Answer 1

有一件事是在python中不需要主要的。另一种方法，就是这样做。

你真的需要一个主？

import os


def CalcAndDisplayShipping(weight):

   UNDER_SIX = 1.1
   TWO_TO_SIX = 2.2
   SIX_TO_TEN = 3.7
   OVER_TEN = 3.8

   shipping = 0.0

   if weight > 10:
      shipping = weight * OVER_TEN
   elif weight > 6:
      shipping = weight * SIX_TO_TEN
   elif weight > 2:
      shipping = weight * TWO_TO_SIX
   else:
      shipping = weight * UNDER_SIX

   print ("Shipping Charge: $", shipping)

weight = float(input("Enter package weight: "))

CalcAndDisplayShipping(weight)

Answer 2

我认为你的意思是：

CalcAndDisplayShipping(main())

这将调用main()并将其返回值作为参数传递给CalcAndDisplayShipping()。

Answer 3

def CalcAndDisplayShipping(weight):

    UNDER_SIX = 1.1
    TWO_TO_SIX = 2.2
    SIX_TO_TEN = 3.7
    OVER_TEN = 3.8

    shipping = 0.0

    if weight > 10:
        shipping = weight * OVER_TEN
    elif weight > 6:
        shipping = weight * SIX_TO_TEN
    elif weight > 2:
       shipping = weight * TWO_TO_SIX
    else:
       shipping = weight * UNDER_SIX

    print ("Shipping Charge: $", shipping)

if __name__ == '__main__':

    weight = float(input("Enter package weight: "))
    CalcAndDisplayShipping(weight)

如果您正在使用python解释器运行此脚本，请执行此操作 python script_name.py，__name__变量值为'__main__'。

如果您要将此模块导入其他模块，__name__将不会__main__，并且它不会执行主要部分。

因此，如果您希望在将此模块作为单个脚本运行时执行任何操作，则可以使用此功能。

这个条件＆＃39;只有在将模块作为单个脚本运行时才满足。

python传递参数模块

3 个答案: