Question

我发现很多方法可以使用Objective-C在UIViewControllers中弹回2 UINavigationController，但是当我尝试将其切换到Swift时，它似乎没有用。

回到UIViewController的最佳方法是什么？任何指导将不胜感激感谢

Answer 1

扩展我的评论，找到viewControllers数组中的第二个最后一个视图控制器，然后使用popToViewController来避免覆盖整个视图控制器堆栈。

示例（假设导航控制器有多个视图控制器）：

func backTwo() {
    let viewControllers: [UIViewController] = self.navigationController!.viewControllers as [UIViewController]
    self.navigationController!.popToViewController(viewControllers[viewControllers.count - 3], animated: true)
}

<强>目标C

NSArray *viewControllers = [self.navigationController viewControllers];
[self.navigationController popToViewController:viewControllers[viewControllers.count - 3] animated:YES];

Answer 2

我写了一个UIViewController扩展（Swift 3+ ready）

您可以这样使用：

/// pop back n viewcontroller
func popBack(_ nb: Int) {
    if let viewControllers: [UIViewController] = self.navigationController?.viewControllers {
        guard viewControllers.count < nb else {
            self.navigationController?.popToViewController(viewControllers[viewControllers.count - nb], animated: true)
            return
        }
    }
}

用法：

self.popBack(3)

奖励解雇特定的视图控制器

/// pop back to specific viewcontroller
func popBack<T: UIViewController>(toControllerType: T.Type) {
    if var viewControllers: [UIViewController] = self.navigationController?.viewControllers {
        viewControllers = viewControllers.reversed()
        for currentViewController in viewControllers {
            if currentViewController .isKind(of: toControllerType) {
                self.navigationController?.popToViewController(currentViewController, animated: true)
                break
            }
        }
    }
}

用法：

self.popBack(toControllerType: MyViewController.self)

Answer 3

您可以在（swift 2.0）

中动态弹出多个viewcontrollers

let allViewController: [UIViewController] = self.navigationController!.viewControllers as [UIViewController];

                        for aviewcontroller : UIViewController in allViewController
                        {
                            if aviewcontroller .isKindOfClass(YourDestinationViewControllerName)
                            {
                             self.navigationController?.popToViewController(aviewcontroller, animated: true)
                            }
                        }

Answer 4

在

中

user5320485回答

let viewControllers = self.navigationController!.viewControllers as [UIViewController];
for aViewController:UIViewController in viewControllers {
    if aViewController.isKind(of: AdCreateViewController.self) {
        _ = self.navigationController?.popToViewController(aViewController, animated: true)
    }
}

Answer 5

@Maximelc的答案的Swift 4 UINavigationController扩展版本：

extension UINavigationController {

    func popBack(_ nb: Int) {
        let viewControllers: [UIViewController] = self.viewControllers
        guard viewControllers.count < nb else {
            self.popToViewController(viewControllers[viewControllers.count - nb], animated: true)
            return
        }
    }

    /// pop back to specific viewcontroller
    func popBack<T: UIViewController>(toControllerType: T.Type) {
        var viewControllers: [UIViewController] = self.viewControllers
        viewControllers = viewControllers.reversed()
        for currentViewController in viewControllers {
            if currentViewController .isKind(of: toControllerType) {
                self.popToViewController(currentViewController, animated: true)
                break
            }
        }
    }

 }

Answer 6

为了方便起见，我做了一个助手：

import Foundation
import UIKit

class NavigationHelper {

    static func back(number: Int, from viewControlller : UIViewController) {
        let viewsBack = number + 1
        let viewControllers: [UIViewController] = viewControlller.navigationController!.viewControllers as [UIViewController]
        viewControlller.navigationController!.popToViewController(viewControllers[viewControllers.count - viewsBack], animated: true)
    }

    static func back(number: Int, from viewControlller: UITableViewController) {
        let viewsBack = number + 1
        let viewControllers: [UIViewController] = viewControlller.navigationController!.viewControllers as [UIViewController]
        viewControlller.navigationController!.popToViewController(viewControllers[viewControllers.count - viewsBack], animated: true)
    }
}

例如，在您的ViewController中，您可以使用NavigationHelper.back(number: 1, from: self)

Answer 7

这里是另一个稍微“防呆”的版本：

extension UINavigationController {
    func popBack(_ count: Int) {
        guard count > 0 else {
            return assertionFailure("Count can not be a negative value.")
        }
        let index = viewControllers.count - count - 1
        guard index > 0 else {
            return assertionFailure("Not enough View Controllers on the navigation stack.")
        }
        popToViewController(viewControllers[index], animated: true)
    }
}

Answer 8

 let allViewControllers : [UIViewController] = self.navigationController!.viewControllers as [UIViewController]
        self.navigationController?.popToViewController(allViewControllers[allViewControllers.count-3], animated: true)

Answer 9

如果您想在特定的视图控制器上弹出，您可以通过在示例代码中将 DestinationViewController 替换为您的视图控制器来搜索该视图控制器。

func moveToDestinationViewController() {
    let viewController = self.navigationController?.viewControllers.first { $0 is DestinationViewController }
    guard let destinationVC = viewController else { return }
    self.navigationController?.popToViewController(destinationVC, animated: true)
}

在Swift中的Nav Controller中弹出2个视图控制器

9 个答案: