我在python 2.7中使用socketserver模块运行python服务器。 OmniPeek数据包分析工具显示TCP握手完成, 但是服务器立即发送一个重置数据包来终止连接。
显示问题的简化服务器代码是:
from threading import Lock, Thread, Condition
import SocketServer
import socket
import sys
import time
class ThreadedTCPRequestHandler(SocketServer.BaseRequestHandler):
def __init__(self, state, *args, **keys):
try:
state['lock'].acquire()
state['client_count'] += 1
finally:
state['lock'].release()
self.state = state
SocketServer.BaseRequestHandler.__init__(self, *args, **keys)
def handle(self):
self.state['lock'].acquire()
count = self.state['client_count']
self.state['lock'].release()
while True:
try:
self.state['lock'].acquire()
running = self.state['running']
self.state['lock'].release()
if not running:
break;
time.sleep(1) # do some work
except Exception as msg:
print msg
print "ThreadedTCPRequestHandler shutting down..."
class ThreadedTCPServer(SocketServer.ThreadingMixIn, SocketServer.TCPServer):
pass
def handler_factory(state):
def createHandler(*args, **keys):
return ThreadedTCPRequestHandler(state, *args, **keys)
return createHandler
if __name__ == "__main__":
lock = Lock()
cv = Condition(lock)
state = {'running': True, 'client_count': 0, 'lock': lock, 'cv': cv}
server = ThreadedTCPServer(('localhost', 12345), handler_factory(state))
server_thread = Thread(target=server.serve_forever)
server_thread.daemon = True
server_thread.start()
print "Server loop running in thread:", server_thread.name
# wait for a client to connect
cv.acquire()
while state['client_count'] == 0 and state['running']:
cv.wait(1.0)
# print msg
cv.release()
# substitute real work here...
time.sleep(5)
lock.acquire()
state['running'] = False
lock.release()
server.shutdown()
和客户端代码:
import socket
if __name__ == "__main__":
try:
client = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
print 'ip: {} port {}'.format('10.4.2.54', 12345)
client.connect(('10.4.2.54', 12345))
while True:
data = client.recv(4096)
if len(data) == 0:
break;
print 'data: {}'.format(data)
client.shutdown(socket.SHUT_RDWR)
client.close()
except Exception as msg:
print msg
服务器代码基于python 2.7 docs serversocket Mixin示例,看起来非常简单,但是......
由于
答案 0 :(得分:0)
不确定您的预期行为是什么,但如果您进行了一些更改,您将能够看到它可以正常工作
替换你的句柄方法
def handle(self):
while True:
try:
data = self.request.recv(1024).strip()
if len(data) != 0:
print data
time.sleep(1) # do some work
self.request.send('test data')
except Exception as msg:
print msg
break
print "ThreadedTCPRequestHandler shutting down..."
和客户(主要内部):
try:
client = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
print 'ip: {} port {}'.format('localhost', 1232)
client.connect(('localhost', 1232))
client.send('test')
n = 0
while True:
data = client.recv(4096)
if len(data) != 0:
print 'data: {}'.format(data)
time.sleep(1)
n += 1
client.send('keep-alive' + str(n) + '\n')
print 'here'
client.shutdown(socket.SHUT_RDWR)
client.close()
except Exception as msg:
print msg
我刚修改它以发送内容和打印内容。但它并没有崩溃。 我认为你的self.state ['lock']。acquire()和release()调用存在问题。我拿出了'运行'检查,因为除了在服务器代码的末尾,它没有被真正使用。 此外,没有任何操作,套接字将超时。
再一次,我并没有声称“修复”了你的问题......而且我不确定你到底在寻找什么...只是帮助你进行头脑风暴!
答案 1 :(得分:0)