Question

我在下面写了代码来连接java web socket服务器。客户端可以成功连接到服务器。（我希望如此）。我的问题是当我删除socket_recv行时，它不会等待并抛出任何错误。但是php在这个行/块上等待无限。

PHP版本是5.5.12

<?php
error_reporting(E_ALL);

$service_port = 2002;

$address = 'x.x.x.x';

$socket = socket_create(AF_INET, SOCK_STREAM, SOL_TCP);
if ($socket === false) {
    echo "socket_create() failed: reason: " . socket_strerror(socket_last_error()) . "\n";
} else {
    echo "OK.\n";
}
$result = socket_connect($socket, $address, $service_port);
if ($result === false) {
    echo "socket_connect() failed.\nReason: ($result) " . socket_strerror(socket_last_error($socket)) . "\n";
} else {
    echo "OK.\n";
}

$input = "(({\"u\":\"994774100040\",\"ut\":0,\"lon\":28.838424,\"lox\":28.941421,\"lax\":41.074951,\"lan\":40.965122,\"rg\":0.0,\"pr\":0.0,\"di\":0.0,\"e\":false,\"p\":0,\"r\":0,\"l\":1,\"cr\":0,\"ac\":2,\"st\":0,\"t\":10,\"a\":5,\"ls\":1}))";
$out = '';

socket_write($socket, $input, strlen($input));
echo "OK.\n";

$buf = '';

//infinite waiting on below line
if (false !== ($bytes = socket_recv($socket, $buf, 1024,0))) {
    echo "Read $bytes bytes from socket_recv(). Closing socket...";
} else {
    echo "socket_recv() failed; reason: " .
    socket_strerror(socket_last_error($socket)) . "\n";
}
socket_close($socket);

echo $buf . "\n";
echo "OK.\n\n";
?>

Answer 1

我解决了添加以下代码进行握手的问题。：

$key = com_create_guid();
$header = "GET  HTTP/1.1\r\n";
$header.= "Upgrade: WebSocket\r\n";
$header.= "Connection: Upgrade\r\n";
$header.= "Host: x.x.x.x:2002\r\n";
$header.= "Origin: http://localhost:81\r\n";
$header.= "Sec-WebSocket-Key: " . $key . "\r\n";
$header.= "\r\n";
socket_write($socket, $header, strlen($header));

Web套接字服务器等待来自客户端的标头以进行握手。

PHP警告：socket_recv（）无限等待

1 个答案: