Question

我正在尝试在LinkedIn中分享一些内容。我正在获取用户个人资料，但我无法使用此代码分享帖子：

[self.client GET:[NSString stringWithFormat:@"https://api.linkedin.com/v1/people/~:(id,picture-url,email-address,first-name,last-name,headline,location,industry,positions,educations)?oauth2_access_token=%@&format=json", accessToken] parameters:nil success:^(AFHTTPRequestOperation *operation, NSDictionary *result) {

        NSLog(@"current user %@", result);

        [self.client POST:[NSString stringWithFormat:@"https://api.linkedin.com/v1/people/~/shares/?comment=test&title=commentTest&oauth2_access_token=%@&format=json",accessToken] parameters:nil success:^(AFHTTPRequestOperation *operation, NSDictionary *result) {
            NSLog(@"result share %@",result);
        } failure:^(AFHTTPRequestOperation *operation, NSError *error) {

            NSLog(@"failed to post %@", error);
        }];

    } failure:^(AFHTTPRequestOperation *operation, NSError *error) {

        NSLog(@"failed to fetch current user %@", error);
    }];

我已经阅读了这篇文档文章https://developer.linkedin.com/documents/writing-linkedin-apis，但我不理解的是，他们是否意味着我们在请求中发布了一个完整的json或xml？如果是这样，你有解决方案吗？

Answer 1

尝试将 Content-Type 和 Accept 添加到http标头。

AFJSONRequestSerializer *requestSerializer = [AFJSONRequestSerializer serializer];
[requestSerializer setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[requestSerializer setValue:@"application/json" forHTTPHeaderField:@"Accept"];
self.client.requestSerializer = requestSerializer;

在LinkedIn中发布/分享状态

1 个答案: