Question

我正在检查当前日期是否是工作日，如果不是，我想获得下一个工作日。工作日是周一至周五。

以下是我的尝试：

import time
from datetime import date,timedelta
dmy=time.strftime("%d-%m-%Y")# getting the current date 
if dmy.strftime("%w") in set([6,7]): # checking if its a weekend( Sat/Sun) , if so advancing
    dmy=time.strftime("%d-%m-%Y")+ timedelta(days=dmy.strftime("%w")%5) # this statement is not working, it errors out .

声明dmy=time.strftime("%d-%m-%Y")+ timedelta(days=dmy.strftime("%w")%5)）无效。什么是推进下一个工作日的最简单方法？

Answer 1

您应该使用实际的date个对象，而不是字符串：

>>> import datetime
>>> today = datetime.date.today()
>>> if today.isoweekday() in set((6, 7)):
    today += datetime.timedelta(days=today.isoweekday() % 5)


>>> today
datetime.date(2014, 9, 30)

请注意，isoweekday为1（星期一）至7（星期日），而weekday为0至6。

另外，请注意您的逻辑目前在星期六增加一天，在星期日增加两天，这是不正确的 - 我认为您想要：

>>> if today.isoweekday() in set((6, 7)):
    today += datetime.timedelta(days=8 - today.isoweekday())

例如：

>>> day = datetime.date(2014, 10, 4)
>>> day
datetime.date(2014, 10, 4) # Saturday
>>> if day.isoweekday() in set((6, 7)):
    day += datetime.timedelta(days=8 - day.isoweekday())


>>> day
datetime.date(2014, 10, 6) # Monday

Answer 2

def calculate_the_next_week_day(day_now):    
    if day_now.isoweekday()== 5:
        day_now += datetime.timedelta(days=3)
    elif day_now.isoweekday()== 6:
        day_now += datetime.timedelta(days=2)
    else:
        day_now += datetime.timedelta(days=1)
    return day_now

Answer 3

答案：

import datetime
    def to_week_day(date):
        if date.isoweekday() in set((6, 7)):
            date += datetime.timedelta(days=-date.isoweekday() + 8)
        return date

说明：

我今天遇到了这个问题，@jonrsharpe的答案对我不起作用，因为date.isoweekday() % 5 = 1在星期六和date.isoweekday() % 5 = 2在星期六，导致下周分别是星期天和星期二，是错的。我不想在代码中使用if语句，所以我要做的就是找到一个函数y = f（x），当x = 6时返回y = 2，而当x = 7时返回y = 1。

此函数为y = -x + 8，在timedelta函数中用作参数。

此答案基于@jonrsharpe的答案，因此您也应该投票给他。

Answer 4

允许任意一天使用get_next_dayofweek_datetime和date_time。

from datetime import datetime as dt
from datetime import timedelta

def get_weekday(day):
    days  = ["mon","tue","wed","thu","fri","sat","sun"]
    return days.index(day) + 1

def get_next_dayofweek_datetime(date_time, dayofweek):
    start_time_w = date_time.isoweekday()
    target_w = get_weekday(dayofweek)
    if start_time_w < target_w:
      day_diff = target_w - start_time_w
    else:
        day_diff = 7 - (start_time_w - target_w)

    return date_time + timedelta(days=day_diff)

start_time = dt.strptime("2020-02-12 20:20:00", "%Y-%m-%d %H:%M:%S") # wednesday


print(get_next_dayofweek_datetime(start_time, "thu"))
print(get_next_dayofweek_datetime(start_time, "fri"))
print(get_next_dayofweek_datetime(start_time, "sat"))
print(get_next_dayofweek_datetime(start_time, "sun"))
print(get_next_dayofweek_datetime(start_time, "mon"))
print(get_next_dayofweek_datetime(start_time, "tue"))
print(get_next_dayofweek_datetime(start_time, "wed"))
print(get_next_dayofweek_datetime(start_time, "thu"))

输出：

2020-02-13 20:20:00
2020-02-14 20:20:00
2020-02-15 20:20:00
2020-02-16 20:20:00
2020-02-17 20:20:00
2020-02-18 20:20:00
2020-02-19 20:20:00
2020-02-13 20:20:00

得到下一个工作日的日期

4 个答案: