Question

我有一个REST API返回的JSON字符串：

'{"success":true,"product":{"id":"2","category_id":"2","type":"9","name":".ch","description":"","visible":"1","domain_options":"0","stock":"0","qty":"0","autosetup":"2","subdomain":"","owndomain":"0","tax":"0","upgrades":"","sort_order":"0","client_limit":"0","rel":"Product","paytype":"DomainRegular","m_setup":"0.00","q_setup":"0.00","s_setup":"0.00","a_setup":"0.00","b_setup":"0.00","t_setup":"0.00","p4_setup":"0.00","p5_setup":"0.00","d_setup":"0.00","w_setup":"0.00","h_setup":"0.00","m":"0.00","q":"0.00","s":"0.00","a":"0.00","b":"0.00","t":"0.00","p4":"0.00","p5":"0.00","d":"0.00","w":"0.00","h":"0.00","ptype":"DomainsType","options":"3","module":"13","server":"","tlds":null,"periods":{"1":{"product_id":"2","period":"1","register":"17.00","transfer":"17.00","renew":"17.00"}},"tag_name":".ch","tag_description":"","free_domain":"0","product_id":"2","not_renew":"0","epp":true,"ns":["ns3.dfinet.ch","ns4.dfinet.ch","",""],"nsips":"|||","tld":".ch","nsip":["","","",""],"asciimode":true,"app_id":"1","app_ns1":"","app_ns2":"","app_ns3":"","app_ns4":"","app_ip1":"","app_ip2":"","app_ip3":"","app_ip4":"","emails":{"AfterRegistrarRegistration":"28","AfterRegistrarRenewal":"29","AfterRegistrarTransfer":"30","expiringDomain":"54"}},"config":false,"call":"getProductDetails","server_time":1412061849}'

我正在尝试将其转换为对象，然后为soap webservice提供XML，我到目前为止所做的是

从其余API检索结果 - ＆gt;使用 json_decode（$ obj）
使用转换后的对象

问题在于，使用以下JSON，有一些属性是“数字”但不是顺序的，因此JSON将字符串转换为对象，如下所示：

$o = new stdClass();
$o->1 = 'a string';

问题是当soap将对象转换为XML时，名为＆lt; 1＆gt; 的节点是无效的XML标记。

我可以做什么来“预解析”JSON并将所有这些虚假对象转换为序列数组？

编辑：基于 dmikam 答案的解决方案

我根据提出的解决方案做了一些更清洁的事情：

function fixVariables($variables)
{
    if (!is_array($variables) && !is_object($variables)) {
        return $variables;
    }

    foreach ($variables as $k => &$variable) {

        if (is_object($variable)) {

            if (is_numeric(key($variable))) {
                $values = array();
                foreach ($variable as $value) {
                    $values[] = $value;
                }
                $variable = $values;
                unset($values);
            }
            $this->fixVariables($variable);

        } elseif (is_array($variable)) {

            if (is_numeric(key($variable))) {
                $variable = array_values($variable);
            }
            $this->fixVariables($variable);
        }
    }

    return $variables;
}

Answer 1

好吧，我认为您可以遍历生成的已解析对象，并将包含数字索引的所有项目转换为数组。功能将是这样的：

function fixJsonObject($obj){
    if (is_object($obj)){
        foreach(get_object_vars($obj) as $key=>$value){
            $obj->$key = fixJsonObject($obj->$key);
            if (is_numeric($key)){
                return (array)$obj;
            }
        }
    }elseif (is_array($obj)){
        foreach($obj as $key=>$value){
            $obj[$key] = fixJsonObject($obj[$key]);
        }
    }
    return $obj;        
}

$json = json_decode('{your: "json"}');
$json = fixJsonObject($json);

我测试了一下，看起来很有效。

自定义json_decode行为

1 个答案: