我正在计算用于在饼图中显示的内容。我想用实际的投资类型按数字显示最高6位数,其余为"其他" as investmentType。
SELECT i.investment_type AS investmentType,
COUNT(*) AS investmentCount
FROM investment i,
vertical v
WHERE v.vertical_name = i.investment_type
AND v.type = 'STR'
AND i.status_funding = 'o'
GROUP
BY i.investment_type
ORDER
BY investmentCount desc
以上查询给我一个结果
将limit 6
添加到查询中我得到
我需要的是还有一行有投资类型"其他"和投资金额" 7"。
答案 0 :(得分:1)
您可能想尝试以下内容:
SELECT i.investment_type as investmentType,COUNT(*) as investmentCount FROM investment i,vertical v
WHERE v.vertical_name =i.investment_type AND v.type='STR' AND i.status_funding ='o'
group by i.investment_type order by investmentCount desc
limit 6
UNION
SELECT "others" as investmentType, SUM(othersInvestmentCount) as investmentCount FROM (
SELECT COUNT(*) as othersInvestmentCount FROM investment i,vertical v
WHERE v.vertical_name =i.investment_type AND v.type='STR' AND i.status_funding ='o'
group by i.investment_type order by investmentCount desc
limit 6, 4294967296
)
我没有测试此查询,如果发现语法问题,可以编辑它。涉及三个实际查询,但它不应该是疯狂的慢(如果不需要更快,那么就不需要更快地尝试)。
我假设您的数据库中记录的记录少于2 ^ 32,这对于MySQL数据库来说似乎是一个非常合理的假设(但如果您觉得不安全,只需将其替换为2 ^ 64)。