我不知道我做错了什么,我的所有其他服务都没有问题。我正在尝试做的是上传照片。最初代码的服务部分是在控制器内部,我重构它是一个服务,因为我不想在编辑照片后再写一组代码再次上传(这是什么服务的权利?)
控制器:
app.controller('UploadCtrl', ['$scope', '$upload','UploadService',
function($scope, $upload,UploadService) {
$scope.uploads = [];
var photos = $scope.$parent.photos;
for (i = 0; i < 3; i++) {
$scope.uploads[i] = {
id: i+1,
showLink: photos[i].showLink,
showProg: false,
progress: 0,
photoUrl: photos[i].dataUrl
}
}
}
]);
工厂:
app.factory('UploadService',['$upload', '$scope', function($upload,$scope){
$scope.onFileSelect = function($files, $_upload) {
for (var i = 0; i < $files.length; i++) {
var $file = $files[i];
//set thumbnail
$scope.dataUrl = null;
if ($file.type.indexOf('image') > -1) {
var fileReader = new FileReader();
fileReader.readAsDataURL($file)
var loadFile = function(fileReader) {
fileReader.onload = function(e) {
// console.log(e.target.result);
$_upload.dataUrl = e.target.result;
$_upload.showLink = false;
$_upload.showProg = true;
}
}(fileReader);
}
$scope.upload = $upload.upload({
url: 'upload_picture',
method: 'POST',
file: $file,
fileFormDataName: 'provider[photo_' + $_upload.id + ']'
}).progress(function(event) {
$_upload.progress = parseInt(100.0 * event.loaded / event.total);
// console.log('percent: ' + $_upload.progress);
}).success(function(data, status, headers, config) {
// file is uploaded successfully
// console.log("success")
// console.log(data);
$_upload.showProg = false;
}).error(function(data, status, headers, config) {
console.log("error");
});
}
};
var UploadService = $scope.onFileSelect($files,$upload);
return UploadService;
}]);
答案 0 :(得分:2)
首先,服务不能依赖于范围,因此您不能注入$ scope(可以注入$ rootScope)。您无法从控制器实现中复制和粘贴代码并粘贴到服务中。 工厂服务需要创建服务对象,然后附加功能并最后返回
app.factory('UploadService',['$upload', function($upload){
var service = {};
service.upload = $upload.upload({
...
});
return service;
}]);
答案 1 :(得分:1)
您无法将$ scope注入工厂/服务。您可以使用$ rootScope,但您可能应该从工厂返回一个承诺。
这是另一个类似的问题。 Angularjs factory: errors on passing $scope,$route,$http?
app.factory('UploadService',['$upload', '$q', function($upload, $q){
var deferred = $q.defer();
return{
upload: function(uploadConfig){
$upload.upload(uploadConfig)
.success(function(data){
deferred.resolve(data);
}).error(function(error){
deferred.reject(error);
});
return deferred.promise;
}
}
}]);